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anonymous

  • one year ago

can somebody help me plot these constraints

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  1. anonymous
    • one year ago
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    \[x+y \le12\]

  2. freckles
    • one year ago
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    do you know how to graph the line y=-x+12?

  3. anonymous
    • one year ago
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    nope

  4. freckles
    • one year ago
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    do you know how to find y when x=-1? or do you know how to find y when x=1?

  5. anonymous
    • one year ago
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    no

  6. freckles
    • one year ago
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    what is y when x=-1? replace x with -1 and find out like so: y=-(-1)+12 evaluate/simplify what is y when x=1? replace x with 1 and find out like so: y=-(1)+12 evaluate/simplify

  7. freckles
    • one year ago
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    If you aren't sure what I'm asking, I'm asking you to do the following: Evaluate -(-1)+12 and Evaluate -1+12

  8. anonymous
    • one year ago
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    11

  9. freckles
    • one year ago
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    -1+12=11 but -(-1)+12=1+12=13 so when x=-1 you have y=-(-1)+12=13 and so when x=1 you have y=-(1)+12=-1+12=11 So you can graph the ordered pairs (-1,13) and (1,11) as a start to plotting the line. Then once we have the line we have to work with the inequality part.

  10. freckles
    • one year ago
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    |dw:1434654369343:dw| plotted the points not just connect the dots and extend your line passed the dots

  11. freckles
    • one year ago
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    |dw:1434654419427:dw|

  12. anonymous
    • one year ago
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    is it both of them or only one

  13. freckles
    • one year ago
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    now your inequality said: \[x+y \le 12 \\ \text{ subtracting the } x \text{ on both says } y \le -x+12 \\ \text{ and that is why I graphed the line } y=-x+12\] now you already have the equal part of your inequality. Now y<-x+12 means you want to shade below your line.

  14. freckles
    • one year ago
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    what do you mean?

  15. freckles
    • one year ago
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    I plotted both points.

  16. freckles
    • one year ago
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    and connected the dots.

  17. freckles
    • one year ago
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    do you know why we shade below the line for y<-x+12? It is because that represents all the ordered pairs with a y value less than any point that falls on the line.

  18. anonymous
    • one year ago
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    i got it now thanks very much

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