anonymous
  • anonymous
can somebody help me plot these constraints
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
\[x+y \le12\]
freckles
  • freckles
do you know how to graph the line y=-x+12?
anonymous
  • anonymous
nope

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freckles
  • freckles
do you know how to find y when x=-1? or do you know how to find y when x=1?
anonymous
  • anonymous
no
freckles
  • freckles
what is y when x=-1? replace x with -1 and find out like so: y=-(-1)+12 evaluate/simplify what is y when x=1? replace x with 1 and find out like so: y=-(1)+12 evaluate/simplify
freckles
  • freckles
If you aren't sure what I'm asking, I'm asking you to do the following: Evaluate -(-1)+12 and Evaluate -1+12
anonymous
  • anonymous
11
freckles
  • freckles
-1+12=11 but -(-1)+12=1+12=13 so when x=-1 you have y=-(-1)+12=13 and so when x=1 you have y=-(1)+12=-1+12=11 So you can graph the ordered pairs (-1,13) and (1,11) as a start to plotting the line. Then once we have the line we have to work with the inequality part.
freckles
  • freckles
|dw:1434654369343:dw| plotted the points not just connect the dots and extend your line passed the dots
freckles
  • freckles
|dw:1434654419427:dw|
anonymous
  • anonymous
is it both of them or only one
freckles
  • freckles
now your inequality said: \[x+y \le 12 \\ \text{ subtracting the } x \text{ on both says } y \le -x+12 \\ \text{ and that is why I graphed the line } y=-x+12\] now you already have the equal part of your inequality. Now y<-x+12 means you want to shade below your line.
freckles
  • freckles
what do you mean?
freckles
  • freckles
I plotted both points.
freckles
  • freckles
and connected the dots.
freckles
  • freckles
do you know why we shade below the line for y<-x+12? It is because that represents all the ordered pairs with a y value less than any point that falls on the line.
anonymous
  • anonymous
i got it now thanks very much

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