Write an indirect proof to show that the diagonals of a parallelogram bisect one another.

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- anonymous

Write an indirect proof to show that the diagonals of a parallelogram bisect one another.

- chestercat

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- anonymous

I need to check my answer!

- anonymous

Let's assume that the diagonals of a parallelogram do not bisect one another. A parallelogram has four sides and it's opposite angles and sides are congruent and parallel. If it's opposite sides are parallel and congruent, and so are it's angles, then the diagonals of a parallelogram must intersect each other.

- anonymous

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- anonymous

@Whitemonsterbunny17

- P0sitr0n

Seems that here you are proving that they intersect and not that they bisect

- anonymous

What's the difference between intersection and bisection?

- anonymous

I thought they were the same. :/

- P0sitr0n

so intersection is that two lines meet at the same point
bisection is that they meet at the same point AND this point splits them in two equal segments

- anonymous

Wait, I think I remember, bisection means they cut eachothe rin halves

- P0sitr0n

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- anonymous

Ahh, okay! I forgot completely.

- P0sitr0n

But the start of your proof seemed reasonable, you should elaborate further

- Loser66

Remind: Should state that parallelogram is not a reflex quadrilateral, hence their diagonals intersect.

- anonymous

Thank you, I'm understanding better now. But do you think you could give me a hint to get started on when else I should be writing, please?

- anonymous

Is this one okay?
Let's assume that the diagonals of a parallelogram do not bisect one another. A parallelogram has four sides and it's opposite angles and opposite sides are congruent and parallel. If the diagonals of a parallelogram intersect each other, and a parallelogram's opposite angles and opposite sides are congruent and parallel, then the intersecting diagonals must also be bisecting one another.

- anonymous

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