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anonymous

  • one year ago

Write an indirect proof to show that the diagonals of a parallelogram bisect one another.

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  1. anonymous
    • one year ago
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    I need to check my answer!

  2. anonymous
    • one year ago
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    Let's assume that the diagonals of a parallelogram do not bisect one another. A parallelogram has four sides and it's opposite angles and sides are congruent and parallel. If it's opposite sides are parallel and congruent, and so are it's angles, then the diagonals of a parallelogram must intersect each other.

  3. anonymous
    • one year ago
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    @Abhisar @ganeshie8

  4. anonymous
    • one year ago
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    @Whitemonsterbunny17

  5. P0sitr0n
    • one year ago
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    Seems that here you are proving that they intersect and not that they bisect

  6. anonymous
    • one year ago
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    What's the difference between intersection and bisection?

  7. anonymous
    • one year ago
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    I thought they were the same. :/

  8. P0sitr0n
    • one year ago
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    so intersection is that two lines meet at the same point bisection is that they meet at the same point AND this point splits them in two equal segments

  9. anonymous
    • one year ago
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    Wait, I think I remember, bisection means they cut eachothe rin halves

  10. P0sitr0n
    • one year ago
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    |dw:1434654690056:dw|

  11. anonymous
    • one year ago
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    Ahh, okay! I forgot completely.

  12. P0sitr0n
    • one year ago
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    But the start of your proof seemed reasonable, you should elaborate further

  13. Loser66
    • one year ago
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    Remind: Should state that parallelogram is not a reflex quadrilateral, hence their diagonals intersect.

  14. anonymous
    • one year ago
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    Thank you, I'm understanding better now. But do you think you could give me a hint to get started on when else I should be writing, please?

  15. anonymous
    • one year ago
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    Is this one okay? Let's assume that the diagonals of a parallelogram do not bisect one another. A parallelogram has four sides and it's opposite angles and opposite sides are congruent and parallel. If the diagonals of a parallelogram intersect each other, and a parallelogram's opposite angles and opposite sides are congruent and parallel, then the intersecting diagonals must also be bisecting one another.

  16. anonymous
    • one year ago
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    @Abhisar

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