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anonymous

  • one year ago

A metal rod is placed in a rectangular box as shown in the figure. How long is the rod? Round your answer to the nearest tenth of an inch, if necessary. A. 5.0 in. B. 12.1 in. C. 13.4 in. D. 14.2 in.

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  1. anonymous
    • one year ago
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    @xapproachesinfinity

  2. anonymous
    • one year ago
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  3. xapproachesinfinity
    • one year ago
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    first we begin by finding the length of the diagonal of the bottom rectangle we use Pythagoras again that diagonal is a hypethenus if you can see it

  4. anonymous
    • one year ago
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    ok

  5. xapproachesinfinity
    • one year ago
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    so heypethenus = sqrt{3^2+4^2}=sqrt{9+16}=sqrt{25}=5 inch

  6. xapproachesinfinity
    • one year ago
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    now we look at the triangle from by the the metal rod we have the long side is 11 inch and the short one we just found is 5 the rod is like a hypotenuse in that triangle so the length of the rod = sqrt{5^2+11^2}=sqrt{25+121}=sqrt{146}

  7. xapproachesinfinity
    • one year ago
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    to the nearest 10th it is 12.08 inch

  8. xapproachesinfinity
    • one year ago
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    you got it ?

  9. anonymous
    • one year ago
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    is that the answer?

  10. anonymous
    • one year ago
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    wouldn't it be 12.1?

  11. xapproachesinfinity
    • one year ago
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    nearest tenth you look at two digits after decimal

  12. anonymous
    • one year ago
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    did you see the answer choices? It also says tenth if an inch.

  13. xapproachesinfinity
    • one year ago
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    i'm sorry it should be one digit after decimal fasting effects haha

  14. xapproachesinfinity
    • one year ago
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    so you are correct

  15. anonymous
    • one year ago
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    so it is 12.1

  16. xapproachesinfinity
    • one year ago
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    yes

  17. anonymous
    • one year ago
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    ok next?

  18. xapproachesinfinity
    • one year ago
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    ok go ahead! next i will give some time to do some of it and see where exactly you stuck

  19. xapproachesinfinity
    • one year ago
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    is that ok

  20. anonymous
    • one year ago
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    sure.

  21. xapproachesinfinity
    • one year ago
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    ok then post :)

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