starwars18
  • starwars18
Find all solutions in the interval [0, 2π). cos^2(x) + 2 cos x + 1 = 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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starwars18
  • starwars18
Could it be simplified to (cos(x) + 1)^2?
starwars18
  • starwars18
and i am totally confused how to do it after that
starwars18
  • starwars18
Answers are 2pi, pi, pi/4 and 7pi/4, or pi/2 and 3pi/2

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More answers

Vocaloid
  • Vocaloid
your first step is correct, the next step is to take the square root of both sides
xapproachesinfinity
  • xapproachesinfinity
look at it like \(y^2+2y+1=0\)
starwars18
  • starwars18
so cos(x) = -1 ???
xapproachesinfinity
  • xapproachesinfinity
solve for y tell you found the values then replace y by cosx then solve
xapproachesinfinity
  • xapproachesinfinity
oh yes
Vocaloid
  • Vocaloid
yes! now find every x for which cos(x) = -1
Pawanyadav
  • Pawanyadav
Solve by putting y=cosx At last check values of y only in range of cosx then you will get the answer.
starwars18
  • starwars18
pi?
Vocaloid
  • Vocaloid
yup, good job!
starwars18
  • starwars18
sorry my computer froze for a bit
starwars18
  • starwars18
ty for your help
xapproachesinfinity
  • xapproachesinfinity
what if we extended the domain to (0, 5pi) what are the solutions ?
xapproachesinfinity
  • xapproachesinfinity
@starwars18
starwars18
  • starwars18
-1 + n2pi, n being a real integer from 0 to 2

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