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starwars18
 one year ago
Find all solutions in the interval [0, 2π).
cos^2(x) + 2 cos x + 1 = 0
starwars18
 one year ago
Find all solutions in the interval [0, 2π). cos^2(x) + 2 cos x + 1 = 0

This Question is Closed

starwars18
 one year ago
Best ResponseYou've already chosen the best response.1Could it be simplified to (cos(x) + 1)^2?

starwars18
 one year ago
Best ResponseYou've already chosen the best response.1and i am totally confused how to do it after that

starwars18
 one year ago
Best ResponseYou've already chosen the best response.1Answers are 2pi, pi, pi/4 and 7pi/4, or pi/2 and 3pi/2

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1your first step is correct, the next step is to take the square root of both sides

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2look at it like \(y^2+2y+1=0\)

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2solve for y tell you found the values then replace y by cosx then solve

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1yes! now find every x for which cos(x) = 1

Pawanyadav
 one year ago
Best ResponseYou've already chosen the best response.0Solve by putting y=cosx At last check values of y only in range of cosx then you will get the answer.

starwars18
 one year ago
Best ResponseYou've already chosen the best response.1sorry my computer froze for a bit

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2what if we extended the domain to (0, 5pi) what are the solutions ?

xapproachesinfinity
 one year ago
Best ResponseYou've already chosen the best response.2@starwars18

starwars18
 one year ago
Best ResponseYou've already chosen the best response.11 + n2pi, n being a real integer from 0 to 2
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