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Babynini

  • one year ago

a) sketch curve b) find a rectangular coordinate equation for the curve by eliminating the perimeter x=sec(t), y=tan(t), 0 </= t < pi/2

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  1. Babynini
    • one year ago
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    I simplified x into x= 1/cos(t) and y = sin(t)/cos(t) then y = [sin(t)][1/cos(t)]

  2. Babynini
    • one year ago
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    then plugged x into y and got y=sint(x)

  3. Babynini
    • one year ago
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    eem..I got confused on that second part there because there's lots of ='s xD yeah the first part is easy

  4. Loser66
    • one year ago
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    ok, line by line y^2 = tan^2 t , ok?

  5. Babynini
    • one year ago
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    right

  6. Babynini
    • one year ago
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    yup

  7. Babynini
    • one year ago
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    yeah.aah I see.

  8. Loser66
    • one year ago
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    ok, last line is obvious. right?

  9. Babynini
    • one year ago
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    Yep!!

  10. Babynini
    • one year ago
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    well the sec^2t= x^2 makes sense

  11. Babynini
    • one year ago
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    how you got to x^2-1=y^2 I don't know.

  12. Loser66
    • one year ago
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    how cannot? y^2 +1 = x^2 just -1 both sides

  13. Babynini
    • one year ago
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    Oooh sorry, i had written it wrong on my paper. k.

  14. Babynini
    • one year ago
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    it could also be written x^2-y^2=1 right?

  15. Loser66
    • one year ago
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    sure

  16. Babynini
    • one year ago
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    then we just plug in numbers for x and find y.

  17. Babynini
    • one year ago
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    Kk's thanks! :)

  18. Loser66
    • one year ago
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    hihihi... tip for a) x^2 -y^2 =1 is a hyperbola with the center at origin

  19. Babynini
    • one year ago
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    Oo that is helpful.

  20. Babynini
    • one year ago
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    Hold up, how do I find the perimeter?

  21. Babynini
    • one year ago
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    like they give me 0 </= t </= pi/2 but I have to do that for x and y

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