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Babynini
 one year ago
a) sketch curve
b) find a rectangular coordinate equation for the curve by eliminating the perimeter
x=sec(t), y=tan(t), 0 </= t < pi/2
Babynini
 one year ago
a) sketch curve b) find a rectangular coordinate equation for the curve by eliminating the perimeter x=sec(t), y=tan(t), 0 </= t < pi/2

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Babynini
 one year ago
Best ResponseYou've already chosen the best response.0I simplified x into x= 1/cos(t) and y = sin(t)/cos(t) then y = [sin(t)][1/cos(t)]

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0then plugged x into y and got y=sint(x)

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0eem..I got confused on that second part there because there's lots of ='s xD yeah the first part is easy

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1ok, line by line y^2 = tan^2 t , ok?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1ok, last line is obvious. right?

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0well the sec^2t= x^2 makes sense

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0how you got to x^21=y^2 I don't know.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1how cannot? y^2 +1 = x^2 just 1 both sides

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0Oooh sorry, i had written it wrong on my paper. k.

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0it could also be written x^2y^2=1 right?

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0then we just plug in numbers for x and find y.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1hihihi... tip for a) x^2 y^2 =1 is a hyperbola with the center at origin

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0Hold up, how do I find the perimeter?

Babynini
 one year ago
Best ResponseYou've already chosen the best response.0like they give me 0 </= t </= pi/2 but I have to do that for x and y
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