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anonymous

  • one year ago

Can someone help me with two questions in conic sections.

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  1. anonymous
    • one year ago
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    1. What is the equation of the following graph?

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  2. anonymous
    • one year ago
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    2. What are the foci of the following graph?

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  3. xapproachesinfinity
    • one year ago
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    i hyperbola has the equation \(\Large \frac{x^2}{a^2}-\frac{y^2}{b^2}=1\) so you need to find a and b

  4. anonymous
    • one year ago
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    how do I find a and b?

  5. xapproachesinfinity
    • one year ago
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    you see that box a is half way from right to left b is half way from bottom up

  6. xapproachesinfinity
    • one year ago
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    so you just take the length of that rectangle and divide into half

  7. xapproachesinfinity
    • one year ago
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    2b=8 so b=4 2a=6 so a=3

  8. anonymous
    • one year ago
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    okay thank you! so the first problem is \[\frac{ x ^{2} }{ 3^{2} }-\frac{ y ^{2} }{ 4^{2} }=1\]

  9. xapproachesinfinity
    • one year ago
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    yes !

  10. anonymous
    • one year ago
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    Can you also help with the 2nd problem

  11. xapproachesinfinity
    • one year ago
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    to find the foci you need to find a and b again then use b^2+c^2=a^2 c=sqrt{a^2-b^2} c is the distance from the foci to the center of that rectangle

  12. xapproachesinfinity
    • one year ago
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    that will get you the coordinates of the foci

  13. xapproachesinfinity
    • one year ago
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    you will find b and a the same way we just did

  14. anonymous
    • one year ago
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    I got A=2 and B=5 is that correct?

  15. xapproachesinfinity
    • one year ago
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    yes!

  16. anonymous
    • one year ago
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    okay what do I do next?

  17. xapproachesinfinity
    • one year ago
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    well i said c is the distance from center to foci so what do you think any idea

  18. xapproachesinfinity
    • one year ago
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    actually an error \(c=\sqrt{a^2+b^2}=\sqrt{29}\) the foci has coordinates (0,c)

  19. anonymous
    • one year ago
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    so c=5.39?

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spraguer (Moderator)
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