Find length and direction of u u = <-4 (sqrt3),4>

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Find length and direction of u u = <-4 (sqrt3),4>

Mathematics
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The initial point is (0,0)|dw:1434670266004:dw|
u = length of u = |u| = sqrt(a^2+b^2) this is the same as saying "the magnitude of vector u"

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Other answers:

direction: theta = arctan(b/a) if theta is negative, and you know for a fact that the vector is in Q2, then add on 180 degrees
oh, I didn't make that connection! ok.
and I didn't know that about direction at all xD thanks :) let me get the answers real quick.
Length = 8 ?
Direction = 178.95
I agree with the length, but not the direction
b/a = 4/(-4*sqrt(3)) = -0.57735026918962 arctan(b/a) = arctan(-0.57735026918962) = -29.9999999999998 which is essentially -30 add on 180 -30+180 = 150
hrm when I do = arctan (4/(-4 sqrt3)) it comes out to = -0.52
you must be in radian mode
...oh xD
Yeah you're right, I was.
if you're using desmos, then click the wrench to change to degree mode
Scientific calculator :) thanks though, I use desmos as well.

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