Babynini
  • Babynini
Find length and direction of u u = <-4 (sqrt3),4>
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Babynini
  • Babynini
The initial point is (0,0)|dw:1434670266004:dw|
Babynini
  • Babynini
@jim_thompson5910 :)
jim_thompson5910
  • jim_thompson5910
u = length of u = |u| = sqrt(a^2+b^2) this is the same as saying "the magnitude of vector u"

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jim_thompson5910
  • jim_thompson5910
direction: theta = arctan(b/a) if theta is negative, and you know for a fact that the vector is in Q2, then add on 180 degrees
Babynini
  • Babynini
oh, I didn't make that connection! ok.
Babynini
  • Babynini
and I didn't know that about direction at all xD thanks :) let me get the answers real quick.
Babynini
  • Babynini
Length = 8 ?
Babynini
  • Babynini
Direction = 178.95
jim_thompson5910
  • jim_thompson5910
I agree with the length, but not the direction
jim_thompson5910
  • jim_thompson5910
b/a = 4/(-4*sqrt(3)) = -0.57735026918962 arctan(b/a) = arctan(-0.57735026918962) = -29.9999999999998 which is essentially -30 add on 180 -30+180 = 150
Babynini
  • Babynini
hrm when I do = arctan (4/(-4 sqrt3)) it comes out to = -0.52
jim_thompson5910
  • jim_thompson5910
you must be in radian mode
Babynini
  • Babynini
...oh xD
Babynini
  • Babynini
Yeah you're right, I was.
jim_thompson5910
  • jim_thompson5910
if you're using desmos, then click the wrench to change to degree mode
Babynini
  • Babynini
Scientific calculator :) thanks though, I use desmos as well.

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