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Babynini

  • one year ago

Find length and direction of u u = <-4 (sqrt3),4>

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  1. Babynini
    • one year ago
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    The initial point is (0,0)|dw:1434670266004:dw|

  2. Babynini
    • one year ago
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    @jim_thompson5910 :)

  3. jim_thompson5910
    • one year ago
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    u = <a,b> length of u = |u| = sqrt(a^2+b^2) this is the same as saying "the magnitude of vector u"

  4. jim_thompson5910
    • one year ago
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    direction: theta = arctan(b/a) if theta is negative, and you know for a fact that the vector is in Q2, then add on 180 degrees

  5. Babynini
    • one year ago
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    oh, I didn't make that connection! ok.

  6. Babynini
    • one year ago
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    and I didn't know that about direction at all xD thanks :) let me get the answers real quick.

  7. Babynini
    • one year ago
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    Length = 8 ?

  8. Babynini
    • one year ago
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    Direction = 178.95

  9. jim_thompson5910
    • one year ago
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    I agree with the length, but not the direction

  10. jim_thompson5910
    • one year ago
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    b/a = 4/(-4*sqrt(3)) = -0.57735026918962 arctan(b/a) = arctan(-0.57735026918962) = -29.9999999999998 which is essentially -30 add on 180 -30+180 = 150

  11. Babynini
    • one year ago
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    hrm when I do = arctan (4/(-4 sqrt3)) it comes out to = -0.52

  12. jim_thompson5910
    • one year ago
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    you must be in radian mode

  13. Babynini
    • one year ago
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    ...oh xD

  14. Babynini
    • one year ago
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    Yeah you're right, I was.

  15. jim_thompson5910
    • one year ago
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    if you're using desmos, then click the wrench to change to degree mode

  16. Babynini
    • one year ago
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    Scientific calculator :) thanks though, I use desmos as well.

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