FAN, FAN TESTIMONIAL, AND MEDAL!!! PLEASE HELP! Rewrite the rational exponent as a radical expression. 3 to the 2 over 3 power, to the 1 over 6 power the sixth root of 3 the ninth root of 3 the eighteenth root of 3 the sixth root of 3 to the third power I know it's not A.

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FAN, FAN TESTIMONIAL, AND MEDAL!!! PLEASE HELP! Rewrite the rational exponent as a radical expression. 3 to the 2 over 3 power, to the 1 over 6 power the sixth root of 3 the ninth root of 3 the eighteenth root of 3 the sixth root of 3 to the third power I know it's not A.

Mathematics
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So it looks like this? \[\frac{ 3^2 }{ 3^{1/6} }\]
or this? \[\left(3^{2/3}\right)^{1/6}\]
Which option is it?

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Other answers:

I'm pretty sure the problem is asking about the second one, but it isn't very clear. When you have a number to an exponent, and that quantity to another power, you multiply the two exponents. So, \(\frac{2}{3} \times \frac{1}{6}\)
1/9
Exactly. So, that is the ninth root of 3.
Thank you! Can you please help me with another one?
sure
Explain how the Quotient of Powers was used to simplify this expression. 5 to the fourth power, over 25 = 52 By simplifying 25 to 52 to make both powers base five, and subtracting the exponents By simplifying 25 to 52 to make both powers base five, and adding the exponents By finding the quotient of the bases to be, one fifth and cancelling common factors By finding the quotient of the bases to be, one fifthand simplifying the expression
The first option is correct. \(5^4/5^2 = 5^{4-2} = 5^2 = 25\)
Thanks! Sorry, but could you help me with a couple more?
Rewrite the rational exponent as a radical by extending the properties of integer exponents. 2 to the 3 over 4 power, all over 2 to the 1 over 2 power the eighth root of 2 to the third power the square root of 2 to the 3 over 4 power the fourth root of 2 the square root of 2
@hahagotem plz help i'll fan you too
Since these two exponents are divided, you have \(2^{3/4 - 1/2}\).
1/4?
Yes, you get \(2^{1/4}\). When you have a number to a fractional exponent, it is a root. So, \(2^{1/4}\) is the fourth root of 2.
So C?
yes
I have 1 more can u plz help?
absolutely.
A rectangle has a length of the fifth root of 16 inches and a width of 2 to the 1 over 5 power inches. Find the area of the rectangle. 2 to the 3 over 5 power inches squared 2 to the 4 over 5 power inches squared 2 inches squared 2 to the 2 over 5 power inches squared
I'm sorry to rush, but I have to get off soon
Thanks!
@Jacob902 is correct. \(2^{4/5} \times 2^{1/5} = 2\)
why ?
\(16 = 2^4\), so the fifth root of 16 is \(2^{4/5}\). When you multiply two exponents with the same base, you add the two powers together. \(2^1 = 2\).

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