anonymous
  • anonymous
FAN, FAN TESTIMONIAL, AND MEDAL!!! PLEASE HELP! Rewrite the rational exponent as a radical expression. 3 to the 2 over 3 power, to the 1 over 6 power the sixth root of 3 the ninth root of 3 the eighteenth root of 3 the sixth root of 3 to the third power I know it's not A.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
BTaylor
  • BTaylor
So it looks like this? \[\frac{ 3^2 }{ 3^{1/6} }\]
BTaylor
  • BTaylor
or this? \[\left(3^{2/3}\right)^{1/6}\]
anonymous
  • anonymous
Which option is it?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

BTaylor
  • BTaylor
I'm pretty sure the problem is asking about the second one, but it isn't very clear. When you have a number to an exponent, and that quantity to another power, you multiply the two exponents. So, \(\frac{2}{3} \times \frac{1}{6}\)
anonymous
  • anonymous
1/9
BTaylor
  • BTaylor
Exactly. So, that is the ninth root of 3.
anonymous
  • anonymous
Thank you! Can you please help me with another one?
BTaylor
  • BTaylor
sure
anonymous
  • anonymous
Explain how the Quotient of Powers was used to simplify this expression. 5 to the fourth power, over 25 = 52 By simplifying 25 to 52 to make both powers base five, and subtracting the exponents By simplifying 25 to 52 to make both powers base five, and adding the exponents By finding the quotient of the bases to be, one fifth and cancelling common factors By finding the quotient of the bases to be, one fifthand simplifying the expression
BTaylor
  • BTaylor
The first option is correct. \(5^4/5^2 = 5^{4-2} = 5^2 = 25\)
anonymous
  • anonymous
Thanks! Sorry, but could you help me with a couple more?
anonymous
  • anonymous
Rewrite the rational exponent as a radical by extending the properties of integer exponents. 2 to the 3 over 4 power, all over 2 to the 1 over 2 power the eighth root of 2 to the third power the square root of 2 to the 3 over 4 power the fourth root of 2 the square root of 2
anonymous
  • anonymous
@hahagotem plz help i'll fan you too
BTaylor
  • BTaylor
Since these two exponents are divided, you have \(2^{3/4 - 1/2}\).
anonymous
  • anonymous
1/4?
BTaylor
  • BTaylor
Yes, you get \(2^{1/4}\). When you have a number to a fractional exponent, it is a root. So, \(2^{1/4}\) is the fourth root of 2.
anonymous
  • anonymous
So C?
BTaylor
  • BTaylor
yes
anonymous
  • anonymous
I have 1 more can u plz help?
BTaylor
  • BTaylor
absolutely.
anonymous
  • anonymous
A rectangle has a length of the fifth root of 16 inches and a width of 2 to the 1 over 5 power inches. Find the area of the rectangle. 2 to the 3 over 5 power inches squared 2 to the 4 over 5 power inches squared 2 inches squared 2 to the 2 over 5 power inches squared
anonymous
  • anonymous
I'm sorry to rush, but I have to get off soon
anonymous
  • anonymous
Thanks!
BTaylor
  • BTaylor
@Jacob902 is correct. \(2^{4/5} \times 2^{1/5} = 2\)
Jacob902
  • Jacob902
why ?
BTaylor
  • BTaylor
\(16 = 2^4\), so the fifth root of 16 is \(2^{4/5}\). When you multiply two exponents with the same base, you add the two powers together. \(2^1 = 2\).

Looking for something else?

Not the answer you are looking for? Search for more explanations.