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a and b are arbitrary proportionality constants

\[cost(x)=a\sqrt {x} +\frac{b}{x}\\
cost'(x)=?\]

you can set the first derivative =0 to see if there is a minimum, and check the endpoints

u can rewrite x in terms of a and b from setting the first derivative = 0

the solution is simply a function of the arbitrary constants a and b,

im about to go to sleep :)

thank you by the way.

sure thing, someone els will come and help you though, @Luigi0210

The other two are imaginary, so I think I can ignore them

thats an complex number right?
chose a real number from the 3 solutions

(-2)^(2/3) is complex number

2^(2/3) is a real number :)

If I multiply that out.. will it be considered a real number?

\[ x -> \frac{1.5874010519681996*b^{\frac{2}{3}}}{a^{\frac{2}{3}}} \]

lol, I know I ask the dumbest questions

ah I like that.. I had a lot of 2/3's .. was just thinking they probably factored out..

once again.. you rocked it .. thank you

most welcome ^_^
always happy to help :D