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anonymous

  • one year ago

The point (3, -4) is on the terminal side of an angle θ . What is cos θ?

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  1. misty1212
    • one year ago
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    |dw:1434675068016:dw|

  2. misty1212
    • one year ago
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    find the hypotenuse of that right triangle, lets call it \(h\) it will be \(\cos(\theta)=\frac{3}{h}\)

  3. misty1212
    • one year ago
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    the hypotenuse you can do with your eyeballs if you remember the mother of all right triangles, the 3 - 4 - 5 right triangle or you could use pythagoras if you do not remember that one

  4. anonymous
    • one year ago
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    Through high school ive had sucky math teachers, so i barely learned anything. So, im having to take online classes and im a visual learner and dont know how to do any of this. Its so confusing

  5. misty1212
    • one year ago
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    what you need to know for this is that the cosine is the first coordinate divided by the length of the hypotenuse

  6. misty1212
    • one year ago
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    you are told that the first coordinate is 3 so that is your numerator also the other leg of the triangle has length 4 that means, by pythangoras, since \[3^2+4^2=h^2\] you have \[9+16=h^2\\ 25=h^2\\ 5=h\]

  7. anonymous
    • one year ago
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    here are the answer choices a) - 3/5 b) 3/5 c) -3/4 D) 3/4 E) 3

  8. misty1212
    • one year ago
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    ok which one is it?

  9. anonymous
    • one year ago
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    b

  10. misty1212
    • one year ago
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    yes

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