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anonymous

  • one year ago

Help for a medal???

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  1. anonymous
    • one year ago
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    If -nx2 + tx + c = 0, what is x equal to?

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  2. SolomonZelman
    • one year ago
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    you have to complete the square for the left side. (or I can refer to that "find the vertex form of the left side" )

  3. anonymous
    • one year ago
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    But how would I do that?

  4. SolomonZelman
    • one year ago
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    Ok, at first you need to factor the first two terms out of -n

  5. anonymous
    • one year ago
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    But you see. The thing is, I don't know how to factor when its mostly letters

  6. anonymous
    • one year ago
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    It really confuses me when its letters and not numbers

  7. SolomonZelman
    • one year ago
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    if you know how to factor when you have numbers, it is a good place to start at then

  8. SolomonZelman
    • one year ago
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    \(\large\color{black}{ \displaystyle -nx^2 + tx + c = 0 }\) would you agree with what I did below? \(\large\color{black}{ \displaystyle -nx^2 + \frac{-ntx}{-n} + c = 0 }\)

  9. anonymous
    • one year ago
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    Yup

  10. SolomonZelman
    • one year ago
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    ok, now, each term has -n in it (each of the first 2). take that -n out from the first term.

  11. misty1212
    • one year ago
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    i have an idea use \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] only where you see an \(a\) put\(-n\) , where you see a \(b\) put a \(t\) and leave \(c\) as it is

  12. SolomonZelman
    • one year ago
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    lol. I always there with completing the square. Quad form is definitely better. Nice approach!

  13. anonymous
    • one year ago
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    Alright, thanks you two! By the way misty, LOVE THE HAIR!

  14. SolomonZelman
    • one year ago
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    Do you like my hair ? :)

  15. SolomonZelman
    • one year ago
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    OH, don't tell me I am bold, you will offend me.

  16. anonymous
    • one year ago
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    Haha, yeah! Very purple-ish

  17. misty1212
    • one year ago
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    \[\huge \color\magenta\heartsuit\]

  18. SolomonZelman
    • one year ago
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    have a nice evening ladies. Adios

  19. anonymous
    • one year ago
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    If I knew how to make that heart I would type it right now. <3 That should be good enough though

  20. anonymous
    • one year ago
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    Thanks, you too!

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