anonymous
  • anonymous
Help for a medal???
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
If -nx2 + tx + c = 0, what is x equal to?
1 Attachment
SolomonZelman
  • SolomonZelman
you have to complete the square for the left side. (or I can refer to that "find the vertex form of the left side" )
anonymous
  • anonymous
But how would I do that?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

SolomonZelman
  • SolomonZelman
Ok, at first you need to factor the first two terms out of -n
anonymous
  • anonymous
But you see. The thing is, I don't know how to factor when its mostly letters
anonymous
  • anonymous
It really confuses me when its letters and not numbers
SolomonZelman
  • SolomonZelman
if you know how to factor when you have numbers, it is a good place to start at then
SolomonZelman
  • SolomonZelman
\(\large\color{black}{ \displaystyle -nx^2 + tx + c = 0 }\) would you agree with what I did below? \(\large\color{black}{ \displaystyle -nx^2 + \frac{-ntx}{-n} + c = 0 }\)
anonymous
  • anonymous
Yup
SolomonZelman
  • SolomonZelman
ok, now, each term has -n in it (each of the first 2). take that -n out from the first term.
misty1212
  • misty1212
i have an idea use \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] only where you see an \(a\) put\(-n\) , where you see a \(b\) put a \(t\) and leave \(c\) as it is
SolomonZelman
  • SolomonZelman
lol. I always there with completing the square. Quad form is definitely better. Nice approach!
anonymous
  • anonymous
Alright, thanks you two! By the way misty, LOVE THE HAIR!
SolomonZelman
  • SolomonZelman
Do you like my hair ? :)
SolomonZelman
  • SolomonZelman
OH, don't tell me I am bold, you will offend me.
anonymous
  • anonymous
Haha, yeah! Very purple-ish
misty1212
  • misty1212
\[\huge \color\magenta\heartsuit\]
SolomonZelman
  • SolomonZelman
have a nice evening ladies. Adios
anonymous
  • anonymous
If I knew how to make that heart I would type it right now. <3 That should be good enough though
anonymous
  • anonymous
Thanks, you too!

Looking for something else?

Not the answer you are looking for? Search for more explanations.