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anonymous

  • one year ago

Simplify the expression: 1/ 1+ cot^2 x

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  1. misty1212
    • one year ago
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    HI!!

  2. misty1212
    • one year ago
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    do you know that \[1+\cot^2(x)=\csc^2(x)\]?

  3. Plasmataco
    • one year ago
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    sin(x)

  4. misty1212
    • one year ago
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    lol not quite

  5. Plasmataco
    • one year ago
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    ?

  6. Plasmataco
    • one year ago
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    oh. sin(x) squared.

  7. misty1212
    • one year ago
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    yup

  8. anonymous
    • one year ago
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    i know nothing of this stuff. its so confusing.

  9. misty1212
    • one year ago
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    then skip it it takes a bit of explaining to know why \[1+\cot^2(x)=\csc^2(x)\] and even then if you do not know that cosecent is the reciprocal of sine, then it will still not make sense

  10. Plasmataco
    • one year ago
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    well, here are some important rule: Sin^2(x)+Cos^2(x)=1 1/sin(x)=csc(x)... I forgot a lot XD.

  11. misty1212
    • one year ago
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    if it was me, and i did not want to spend the several hours ( probably a few weeks) learning this stuff, i would do this http://www.wolframalpha.com/input/?i=1%2F%281%2Bcot%5E2%28x%29%29

  12. anonymous
    • one year ago
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    i cant skip it. this is to help me pass my junior year to be a senior

  13. Plasmataco
    • one year ago
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    Also, the sine and cosine law: http://www.cimt.plymouth.ac.uk/projects/mepres/step-up/sect4/index.htm

  14. misty1212
    • one year ago
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    if you really know nothing about this, then you either have to learn it, or you can't do it if you don't know the basic stuff about sine and cosine, none of this is going to make any sense at all, besides the obvious fact that you can't do something you know nothing about

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