anonymous
  • anonymous
Check my answer for a medal?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
SolomonZelman
  • SolomonZelman
hello
Plasmataco
  • Plasmataco
hi
anonymous
  • anonymous
Factor completely 8m^3 - 12m^2 + 4m. I got 4 (2m^3 - 3m^2 + m)

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Plasmataco
  • Plasmataco
well, first step, you should try factoring it out.
SolomonZelman
  • SolomonZelman
lets see: \(\large\color{slate}{\displaystyle \sqrt{(-3)^2-4\cdot2\cdot1}=\sqrt{9-8}=\sqrt{1}=1}\)
anonymous
  • anonymous
Oh no, this is gonna be difficult to choose who I give this medal too
Vocaloid
  • Vocaloid
you're on the right track but you're not quite done yet notice how each of the terms in the parantheses still has m, right? you can factor out m
SolomonZelman
  • SolomonZelman
yeah, your are not done. You can factor it more. (What I did just now, is the discriminant test)
Plasmataco
  • Plasmataco
factor out 4m instead of 4.
SolomonZelman
  • SolomonZelman
factor out of 4m, and even then not done
Plasmataco
  • Plasmataco
now you have 4m(2m^2-3m+1)
anonymous
  • anonymous
Alright. I got 4m (2m^2 - 3m) is this correct?
SolomonZelman
  • SolomonZelman
and as I demostrated with discriminant test, it is factorable
SolomonZelman
  • SolomonZelman
GOOD SO FAR. NOW, LAST STEP
SolomonZelman
  • SolomonZelman
2m^2-3m+1 => 2m^2-2m-m+1
anonymous
  • anonymous
Alright, alright alright. Listen guys, I'm really getting overwhelmed with all of you trying to help. I appreciate you guys trying to help but I can't focus on so many people. So, I will focus on Solomon since he was the first to respond on this post. Sorry
Plasmataco
  • Plasmataco
ok. it's cool.
anonymous
  • anonymous
Sorry
SolomonZelman
  • SolomonZelman
So we are at this point: 4m(2m^2-3m+1)
SolomonZelman
  • SolomonZelman
now, look at 2m^2-3m+1 alone. you can factor it, and I will give you a hint: re-write it as 2m^2-2m-m+1
Plasmataco
  • Plasmataco
u got dis XD
anonymous
  • anonymous
Alright. so I got (-2m+1) (-m+1)
SolomonZelman
  • SolomonZelman
yes, that ic correct.
Plasmataco
  • Plasmataco
YAY!!!
Plasmataco
  • Plasmataco
Pro tip. It is easier to look at when the coefficients are positive.
SolomonZelman
  • SolomonZelman
You can take two negatives out..... it is a little bit strange to me the way you wrote it. What I meant to see was rather. \(\large 2m^2-3m+1\) \(\large 2m^2-2m-m+1\) \(\large 2m(m-1)-m+1\) \(\large 2m(m-1)-1(m-1)\) \(\large \color{red}{2m}(m-1)+\color{red}{-1}(m-1)\) \(\large (2m-1)(m-1)\)
Plasmataco
  • Plasmataco
hint: -1 x -1 = 1
Plasmataco
  • Plasmataco
same.
Plasmataco
  • Plasmataco
nice job tho
SolomonZelman
  • SolomonZelman
You can take two negatives out..... it is a little bit strange to me the way you wrote it. What I meant to see was rather. \(\large 2m^2-3m+1\) \(\large 2m^2-2m-m+1\) \(\large 2m(m-1)-m+1\) \(\large 2m(m-1)-1(m-1)\) \(\large \color{red}{2m}(m-1)+\color{red}{-1}(m-1)\) \(\large (2m-1)(m-1)\)
SolomonZelman
  • SolomonZelman
I mean the way you did it is perfectly fine. As long as it is correct. But I am just letting you know my point of view from the side.
Plasmataco
  • Plasmataco
it's just easier to manage without negative coefficients... nobody likes negative XD
anonymous
  • anonymous
Alright, but the answer (2m-1) (m-1) isn't an option. Well, there is. But, there is a 4m in front of it. 4m(2m - 1) (m - 1)
anonymous
  • anonymous
Would I just go with that?
Plasmataco
  • Plasmataco
what are the options?
SolomonZelman
  • SolomonZelman
yes, because you are factoring 4m(2m^2-3m+1)
SolomonZelman
  • SolomonZelman
you are not factoring just the 2m^2-3m+1 I took a look at it alone, so that we can factor it, but the 4m does't go away.
anonymous
  • anonymous
Alright. Thanks guys! And Plasma, the options are 2m (4m2 - 6m + 2) 4 (2m3 - 3m2 + m) 4m (2m - 1)(m - 1) 4m (2m2 - 3m)
Plasmataco
  • Plasmataco
go with that, we never dropped the 4m.
SolomonZelman
  • SolomonZelman
ok, you pick one:)
Plasmataco
  • Plasmataco
yup.
Plasmataco
  • Plasmataco
all urs
anonymous
  • anonymous
Thanks guys! I appreciate the fact that you walked me through it Solomon! Sadly not a lot of people would be willing to walk me through these problems. But the ones that do are awesome!
Plasmataco
  • Plasmataco
I do this for the pleasure of helping people. plus, solomon told me to walk people through on problems XD
SolomonZelman
  • SolomonZelman
I told you that? Have I? Well in my mind I was like "I hope he isn't giving out answers like many users here do" .... :) lol
SolomonZelman
  • SolomonZelman
Anyway, you welcome.
anonymous
  • anonymous
Yeah, I appreciate that those users just straight up give me the answer. I also want to learn how to do the problem so I won't ask for help as often.
anonymous
  • anonymous
So I would prefer them to walk me through them
SolomonZelman
  • SolomonZelman
ok:)
SolomonZelman
  • SolomonZelman
have a good evening
anonymous
  • anonymous
You too.

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