Check my answer for a medal?

- anonymous

Check my answer for a medal?

- schrodinger

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- SolomonZelman

hello

- Plasmataco

hi

- anonymous

Factor completely 8m^3 - 12m^2 + 4m.
I got 4 (2m^3 - 3m^2 + m)

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## More answers

- Plasmataco

well, first step, you should try factoring it out.

- SolomonZelman

lets see:
\(\large\color{slate}{\displaystyle \sqrt{(-3)^2-4\cdot2\cdot1}=\sqrt{9-8}=\sqrt{1}=1}\)

- anonymous

Oh no, this is gonna be difficult to choose who I give this medal too

- Vocaloid

you're on the right track but you're not quite done yet
notice how each of the terms in the parantheses still has m, right? you can factor out m

- SolomonZelman

yeah, your are not done. You can factor it more.
(What I did just now, is the discriminant test)

- Plasmataco

factor out 4m instead of 4.

- SolomonZelman

factor out of 4m, and even then not done

- Plasmataco

now you have 4m(2m^2-3m+1)

- anonymous

Alright. I got 4m (2m^2 - 3m) is this correct?

- SolomonZelman

and as I demostrated with discriminant test, it is factorable

- SolomonZelman

GOOD SO FAR.
NOW, LAST STEP

- SolomonZelman

2m^2-3m+1 => 2m^2-2m-m+1

- anonymous

Alright, alright alright. Listen guys, I'm really getting overwhelmed with all of you trying to help. I appreciate you guys trying to help but I can't focus on so many people. So, I will focus on Solomon since he was the first to respond on this post. Sorry

- Plasmataco

ok. it's cool.

- anonymous

Sorry

- SolomonZelman

So we are at this point:
4m(2m^2-3m+1)

- SolomonZelman

now, look at 2m^2-3m+1 alone.
you can factor it, and I will give you a hint: re-write it as
2m^2-2m-m+1

- Plasmataco

u got dis XD

- anonymous

Alright. so I got (-2m+1) (-m+1)

- SolomonZelman

yes, that ic correct.

- Plasmataco

YAY!!!

- Plasmataco

Pro tip. It is easier to look at when the coefficients are positive.

- SolomonZelman

You can take two negatives out..... it is a little bit strange to me the way you wrote it.
What I meant to see was rather.
\(\large 2m^2-3m+1\)
\(\large 2m^2-2m-m+1\)
\(\large 2m(m-1)-m+1\)
\(\large 2m(m-1)-1(m-1)\)
\(\large \color{red}{2m}(m-1)+\color{red}{-1}(m-1)\)
\(\large (2m-1)(m-1)\)

- Plasmataco

hint: -1 x -1 = 1

- Plasmataco

same.

- Plasmataco

nice job tho

- SolomonZelman

- SolomonZelman

I mean the way you did it is perfectly fine. As long as it is correct. But I am just letting you know my point of view from the side.

- Plasmataco

it's just easier to manage without negative coefficients... nobody likes negative XD

- anonymous

Alright, but the answer (2m-1) (m-1) isn't an option. Well, there is. But, there is a 4m in front of it. 4m(2m - 1) (m - 1)

- anonymous

Would I just go with that?

- Plasmataco

what are the options?

- SolomonZelman

yes, because you are factoring
4m(2m^2-3m+1)

- SolomonZelman

you are not factoring just the 2m^2-3m+1
I took a look at it alone, so that we can factor it, but the 4m does't go away.

- anonymous

Alright. Thanks guys! And Plasma, the options are
2m (4m2 - 6m + 2)
4 (2m3 - 3m2 + m)
4m (2m - 1)(m - 1)
4m (2m2 - 3m)

- Plasmataco

go with that, we never dropped the 4m.

- SolomonZelman

ok, you pick one:)

- Plasmataco

yup.

- Plasmataco

all urs

- anonymous

Thanks guys! I appreciate the fact that you walked me through it Solomon! Sadly not a lot of people would be willing to walk me through these problems. But the ones that do are awesome!

- Plasmataco

I do this for the pleasure of helping people. plus, solomon told me to walk people through on problems XD

- SolomonZelman

I told you that? Have I? Well in my mind I was like "I hope he isn't giving out answers like many users here do" .... :) lol

- SolomonZelman

Anyway, you welcome.

- anonymous

Yeah, I appreciate that those users just straight up give me the answer. I also want to learn how to do the problem so I won't ask for help as often.

- anonymous

So I would prefer them to walk me through them

- SolomonZelman

ok:)

- SolomonZelman

have a good evening

- anonymous

You too.

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