## anonymous one year ago Check my answer for a medal?

1. SolomonZelman

hello

2. Plasmataco

hi

3. anonymous

Factor completely 8m^3 - 12m^2 + 4m. I got 4 (2m^3 - 3m^2 + m)

4. Plasmataco

well, first step, you should try factoring it out.

5. SolomonZelman

lets see: $$\large\color{slate}{\displaystyle \sqrt{(-3)^2-4\cdot2\cdot1}=\sqrt{9-8}=\sqrt{1}=1}$$

6. anonymous

Oh no, this is gonna be difficult to choose who I give this medal too

7. Vocaloid

you're on the right track but you're not quite done yet notice how each of the terms in the parantheses still has m, right? you can factor out m

8. SolomonZelman

yeah, your are not done. You can factor it more. (What I did just now, is the discriminant test)

9. Plasmataco

factor out 4m instead of 4.

10. SolomonZelman

factor out of 4m, and even then not done

11. Plasmataco

now you have 4m(2m^2-3m+1)

12. anonymous

Alright. I got 4m (2m^2 - 3m) is this correct?

13. SolomonZelman

and as I demostrated with discriminant test, it is factorable

14. SolomonZelman

GOOD SO FAR. NOW, LAST STEP

15. SolomonZelman

2m^2-3m+1 => 2m^2-2m-m+1

16. anonymous

Alright, alright alright. Listen guys, I'm really getting overwhelmed with all of you trying to help. I appreciate you guys trying to help but I can't focus on so many people. So, I will focus on Solomon since he was the first to respond on this post. Sorry

17. Plasmataco

ok. it's cool.

18. anonymous

Sorry

19. SolomonZelman

So we are at this point: 4m(2m^2-3m+1)

20. SolomonZelman

now, look at 2m^2-3m+1 alone. you can factor it, and I will give you a hint: re-write it as 2m^2-2m-m+1

21. Plasmataco

u got dis XD

22. anonymous

Alright. so I got (-2m+1) (-m+1)

23. SolomonZelman

yes, that ic correct.

24. Plasmataco

YAY!!!

25. Plasmataco

Pro tip. It is easier to look at when the coefficients are positive.

26. SolomonZelman

You can take two negatives out..... it is a little bit strange to me the way you wrote it. What I meant to see was rather. $$\large 2m^2-3m+1$$ $$\large 2m^2-2m-m+1$$ $$\large 2m(m-1)-m+1$$ $$\large 2m(m-1)-1(m-1)$$ $$\large \color{red}{2m}(m-1)+\color{red}{-1}(m-1)$$ $$\large (2m-1)(m-1)$$

27. Plasmataco

hint: -1 x -1 = 1

28. Plasmataco

same.

29. Plasmataco

nice job tho

30. SolomonZelman

You can take two negatives out..... it is a little bit strange to me the way you wrote it. What I meant to see was rather. $$\large 2m^2-3m+1$$ $$\large 2m^2-2m-m+1$$ $$\large 2m(m-1)-m+1$$ $$\large 2m(m-1)-1(m-1)$$ $$\large \color{red}{2m}(m-1)+\color{red}{-1}(m-1)$$ $$\large (2m-1)(m-1)$$

31. SolomonZelman

I mean the way you did it is perfectly fine. As long as it is correct. But I am just letting you know my point of view from the side.

32. Plasmataco

it's just easier to manage without negative coefficients... nobody likes negative XD

33. anonymous

Alright, but the answer (2m-1) (m-1) isn't an option. Well, there is. But, there is a 4m in front of it. 4m(2m - 1) (m - 1)

34. anonymous

Would I just go with that?

35. Plasmataco

what are the options?

36. SolomonZelman

yes, because you are factoring 4m(2m^2-3m+1)

37. SolomonZelman

you are not factoring just the 2m^2-3m+1 I took a look at it alone, so that we can factor it, but the 4m does't go away.

38. anonymous

Alright. Thanks guys! And Plasma, the options are 2m (4m2 - 6m + 2) 4 (2m3 - 3m2 + m) 4m (2m - 1)(m - 1) 4m (2m2 - 3m)

39. Plasmataco

go with that, we never dropped the 4m.

40. SolomonZelman

ok, you pick one:)

41. Plasmataco

yup.

42. Plasmataco

all urs

43. anonymous

Thanks guys! I appreciate the fact that you walked me through it Solomon! Sadly not a lot of people would be willing to walk me through these problems. But the ones that do are awesome!

44. Plasmataco

I do this for the pleasure of helping people. plus, solomon told me to walk people through on problems XD

45. SolomonZelman

I told you that? Have I? Well in my mind I was like "I hope he isn't giving out answers like many users here do" .... :) lol

46. SolomonZelman

Anyway, you welcome.

47. anonymous

Yeah, I appreciate that those users just straight up give me the answer. I also want to learn how to do the problem so I won't ask for help as often.

48. anonymous

So I would prefer them to walk me through them

49. SolomonZelman

ok:)

50. SolomonZelman

have a good evening

51. anonymous

You too.