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anonymous
 one year ago
What is the length of stack M N with bar on top ? Round to the nearest tenth of a unit.
units
anonymous
 one year ago
What is the length of stack M N with bar on top ? Round to the nearest tenth of a unit. units

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0WILL FAN AND MEDAL!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you help me @Hero?

Hero
 one year ago
Best ResponseYou've already chosen the best response.0The quickest way to do it is to find the length of the unit segment. Then multiply by the total number of unit segments that span segment MN.

Hero
 one year ago
Best ResponseYou've already chosen the best response.0The unit segment. If you notice, the entire length of MN can be broken down into six equal segments. Of those six smaller segments, if you take one of them, it would represent the unit segment.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you walk me through using numbers I learn better that way.

Hero
 one year ago
Best ResponseYou've already chosen the best response.0When you have understood that, let me know.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0When I said numbers I meant equations... like @Vocaloid does.

Hero
 one year ago
Best ResponseYou've already chosen the best response.0We'll get to that. But first, do you see that there are six unit segments?

Hero
 one year ago
Best ResponseYou've already chosen the best response.0Okay, now all we have to do is take just one of those segments create a right triangle and apply pythagorean theorem. Notice the length of the legs of the triangle is just one unit. The pythagorean theorem is a^2 + b^2 = c^2. If we let a and b represent the length of the legs, then \(1^2 + 1^2 = c^2\) or \(1 + 1 = c^2\) or simply \(2 = c^2\). So \(\sqrt{2} = c\)

Hero
 one year ago
Best ResponseYou've already chosen the best response.0\(c\) is the length of one unit segment. Multiply that by 6 and you'll have the length of \(MN\)

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2surely it is simpler to apply pythag to the entire interval

Hero
 one year ago
Best ResponseYou've already chosen the best response.0In theory, yes, but if properly applied, this is the simpler method.

Hero
 one year ago
Best ResponseYou've already chosen the best response.0Or the more intuitive method.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am NOT good at math at ALL... Sorry.

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2dw:1434682942799:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2dw:1434683007008:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2\[{MN}^2 = (4(2))^2 + (82)^2\\ {MN} = \sqrt{(4(2))^2 + (82)^2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the answer for the equation... is it 4?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2and what is 4  (2) ?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2so you have a right angled triangle, with two sides equal to 6, and you want to find the hypotenuse pythag. says: 6^2 + 6^2 = MN^2

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2ie MN = √ ( 6^2+6^2 )

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2dont forget to take the square root

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2yes!, but careful, the question wants the answer accurate to the nearest tenth of a unit

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok I have 3 more can you help me @UnkleRhaukus ?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2I want to check your final answer for this one before we move on, what is 8.49 with one decimal place values represented only

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So can you help me with the rest?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2perhaps, (close this post and open a new question so the page doesn't get too long )
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