## anonymous one year ago Consider this reaction. 2SO2g+O2g yields to 2SO3g. What volume, in milliliters, is required to react with 0.640 g of SO2 gas at STP?

1. anonymous

We can use the following formulas $m = n M$ where m is the mass, n is moles, and M is the molar mass, so figure out the molar mass of SO2,. And we also have to use another formula $n = \frac{ v }{ V_{STP} }$ we can relate this with our first formula by doing solving for n first. $m = nM \implies n = \frac{ m }{ M }$ now we can plug this into our second equation $\frac{ m }{ M } = \frac{ v }{ V_{STP} } \implies v = \frac{ m V_{STP} }{ M }$ note that $V_{STP} = 22.4 L/mol$

2. anonymous

Thank you for taking time to answer

3. anonymous