anonymous
  • anonymous
Help please?? <3 Find S12 for 1 + 6 + 11 + 16 +… 308 322 336 342
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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hartnn
  • hartnn
so you know the formula for Sum of terms in Arithmetic series?
anonymous
  • anonymous
no
hartnn
  • hartnn
ok, here you go! \(\Large S_n = n/2 (2a+ (n-1)d) \) where a = First term = 1 d = common difference = .... ? can you find? and n = number of terms = 12, because we need sum of 12 terms

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anonymous
  • anonymous
how do you find the common difference?
hartnn
  • hartnn
d = common difference = difference between next term and current term.. like d = 2nd term - 1st term = 3rd term - 2nd term = ..and so on now can you find the d?
anonymous
  • anonymous
so the common difference is 5
hartnn
  • hartnn
thats right! d= 5 :) now plug in all the values in the formula :)
anonymous
  • anonymous
\[s _{12}=12/2(2\times1+(12-1)5)\] Right?
hartnn
  • hartnn
yup, go on!
anonymous
  • anonymous
\[s _{12}=12/2(2\times1(11)5)\]
hartnn
  • hartnn
so whats your final answer ?
anonymous
  • anonymous
i got 12/114 but that's not an option so... I don't know what I did wrong?
hartnn
  • hartnn
12/2 is separate which will evaluate to 6 6 (2+ 55) = ... ?
anonymous
  • anonymous
oh okay so it 342
hartnn
  • hartnn
yes! thats correct :) the whole \(2a + (n-1)d\) is in numerator and not in denominator :)

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