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anonymous
 one year ago
Help please?? <3
Find S12 for 1 + 6 + 11 + 16 +…
308
322
336
342
anonymous
 one year ago
Help please?? <3 Find S12 for 1 + 6 + 11 + 16 +… 308 322 336 342

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hartnn
 one year ago
Best ResponseYou've already chosen the best response.1so you know the formula for Sum of terms in Arithmetic series?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1ok, here you go! \(\Large S_n = n/2 (2a+ (n1)d) \) where a = First term = 1 d = common difference = .... ? can you find? and n = number of terms = 12, because we need sum of 12 terms

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do you find the common difference?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1d = common difference = difference between next term and current term.. like d = 2nd term  1st term = 3rd term  2nd term = ..and so on now can you find the d?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the common difference is 5

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1thats right! d= 5 :) now plug in all the values in the formula :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[s _{12}=12/2(2\times1+(121)5)\] Right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[s _{12}=12/2(2\times1(11)5)\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1so whats your final answer ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got 12/114 but that's not an option so... I don't know what I did wrong?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.112/2 is separate which will evaluate to 6 6 (2+ 55) = ... ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1yes! thats correct :) the whole \(2a + (n1)d\) is in numerator and not in denominator :)
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