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Can you help and explain this to me @Miracrown
We want to know which direction the ellipse is facing,right?
|dw:1434706786352:dw| let's start with graphing the points given
|dw:1434706818149:dw| these are the points given to us ^ based off of these point,s how do you think we would draw the ellipse?
So, since its (6,0) it would be six units to the right of the center of the figure, right?
yes 6 units to the right of the center and then the co-vertex is 4 units up
Can we also draw those same points flipped over to the other sides?
Yes, we can.
Well, I'd think we can?
Yes, we can. :)
Sorry, I'm not so good that this kind of math.
|dw:1434707098173:dw| so now can we fill in the ellipse from here?
it's ok, don't be sorry - you're learnin'
I'm a little confused. Couldn't it be both horizontal and vertical at this point?
|dw:1434707170902:dw| which direction is our ellipse facing?
Well, if it was a perfect circle then it would be identical from both directions, but since our ellipse is squeeze whichever is the larger portion of the ellipse will be the direction of the ellipse
I would be going horizontal, right? Since it's longer horizontal, or is there a better way of explaining that?
That is exactly it! Since the distance is stretched further along the x-axis it will be horizontal
Thank you so much! I understand now, you've helped a lot! Thank you for helping me so late, I hope you have a wonderful day/night!