A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

please helpppppppp...... medals and fan question in comments

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Michele_Laino help me once again

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    British curriculum?

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what ?

  5. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    please wait, I'm working on your question...

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay...

  7. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    here is my reasoning: |dw:1434709278703:dw| we have: \[\Large L = 2r\sin x\]

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thank you...

  9. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    now, using the theorem of Pitagora, we can write: \[\begin{gathered} \sqrt {4{r^2} - A{B^2}} = 2r\sin x \hfill \\ \sqrt {4{r^2} - A{B^2}} = 2r\sqrt {1 - {{\left( {\cos x} \right)}^2}} \hfill \\ 2r\sqrt {1 - {{\left( {\frac{{AB}}{{2r}}} \right)}^2}} = 2r\sqrt {1 - {{\left( {\cos x} \right)}^2}} \hfill \\ \end{gathered} \]

  10. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    \[\Large \begin{gathered} \sqrt {4{r^2} - A{B^2}} = 2r\sin x \hfill \\ \sqrt {4{r^2} - A{B^2}} = 2r\sqrt {1 - {{\left( {\cos x} \right)}^2}} \hfill \\ 2r\sqrt {1 - {{\left( {\frac{{AB}}{{2r}}} \right)}^2}} = 2r\sqrt {1 - {{\left( {\cos x} \right)}^2}} \hfill \\ \end{gathered} \]

  11. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    so, by comparison, we can write: \[\large \cos x = \frac{{AB}}{{2r}}\]

  12. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    now, using the condition of your problem, we can write: \[\large \begin{gathered} AB + AC + arc(BC) = \pi r \hfill \\ 2AB + 2xAB = \pi r \hfill \\ 2AB\left( {1 + x} \right) = \pi r \hfill \\ AB = \frac{{\pi r}}{{2\left( {1 + x} \right)}} \hfill \\ \end{gathered} \] since, by definition of radians we can write: \[\large arc(BC) = 2xAB\]

  13. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    now substitute the value of AB, into the expression for cos x, what do you get?

  14. alekos
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    brilliant!

  15. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    thanks!! :) @alekos

  16. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks @Michele_Laino

  17. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    :) @yajna

  18. alekos
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    it all follows through quite nicely. how the hell you came up with that so quickly astounds me

  19. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Michele_Laino is a genius @alekos

  20. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    btw @yajna this is the hardest question of this type you can hope to find in p3. So don't stress yourself too much if you find it hard the first time.

  21. Miracrown
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    A true genius she is! @Michele_Laino :)

  22. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes...

  23. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    thanks! @Miracrown

  24. alekos
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @michele what do you do for a living?

  25. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    at the moment I have no job!

  26. alekos
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you've got to be kidding! what sort of job are you looking for?

  27. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    for example teacher, draftsman or translator from English to Italian. my last job was to translate texts of patents

  28. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    from English to Italian

  29. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    and my preceding job was nautical draughtsman

  30. alekos
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    have you been out of work for long?

  31. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    at the moment I am without job from at least 10 months!

  32. alekos
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i am sure you will find another job soon. keep looking and it will happen. you're a smart lady and you deserve it.

  33. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 4

    Thanks for your encouragement!! :) nevertheless, please keep in mind that I'm a male, Lol!!

  34. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.