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anonymous
 one year ago
What is the xcoordinate for the minimum point in the function f(x) = 4 cos(2x − π) from x = 0 to x = 2π?
x = pi over 2
x = pi over 4
x = 2π
x = π
anonymous
 one year ago
What is the xcoordinate for the minimum point in the function f(x) = 4 cos(2x − π) from x = 0 to x = 2π? x = pi over 2 x = pi over 4 x = 2π x = π

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@aloud @phi @mathmate

phi
 one year ago
Best ResponseYou've already chosen the best response.0do you know what cos looks like from 0 to 2pi? https://www.google.com/search?q=cos%28x%29&gbv=2&sei=FSSEVeKzLIevsAWqqoKYAQ

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i thought it intercepts at 4

phi
 one year ago
Best ResponseYou've already chosen the best response.0the smallest value will be y= 4 for a "normal cosine" from 0 to 2pi, the minimum value is at pi (exactly half way from 0 to 2pi)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no I dont know how to graph them that well

phi
 one year ago
Best ResponseYou've already chosen the best response.0so you want to find where the "angle" of your problem f(x) = 4 cos(2x − π) from x = 0 to x = 2π equals pi in other words, what is "x" so that 2x  pi = pi

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would you plug in the x=0 for the x in 2xpi=pi

phi
 one year ago
Best ResponseYou've already chosen the best response.0The easiest way is to look at a graph: https://www.google.com/search?q=cos%28x%29&gbv=2&sei=FSSEVeKzLIevsAWqqoKYAQ#q=4+cos%282x+%E2%88%92+%CF%80%29

phi
 one year ago
Best ResponseYou've already chosen the best response.0but using algebra 2x  pi = pi add +pi to both sides 2x  pi + pi = pi+pi on the left pi+pi add up to zero. on the right you get 2pi 2x = 2pi now divide both sides by 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it would be x=pi because the 2's would cancel right?
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