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anonymous

  • one year ago

Y=3-logx How is this done??

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  1. UnkleRhaukus
    • one year ago
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    Is that \[y = \log_3(x)\]? use the log identity \[y = \log_b(x)\qquad\iff\qquad b^y=x \]

  2. anonymous
    • one year ago
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    Yeah I know that but how is it done with a negative between 3 and logx

  3. anonymous
    • one year ago
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    the answer is y=10^3-y but how

  4. UnkleRhaukus
    • one year ago
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    oh it is a negative? like this \[y = 3-\log(x)\]?

  5. UnkleRhaukus
    • one year ago
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    sorry for my earlier misinterpretation.

  6. anonymous
    • one year ago
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    No its suppose to be a negative between the three and y

  7. UnkleRhaukus
    • one year ago
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    oh , right i erred \[y = 3 - \log (x)\\ \log(x) = 3-y\\ x = 10^{3-y}\]

  8. UnkleRhaukus
    • one year ago
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    Is this what you were looking for?

  9. anonymous
    • one year ago
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    Wait so what exactly did you do?

  10. UnkleRhaukus
    • one year ago
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    \[y = 3 - \log (x)\]add log x to both sides of the equation, \[y+\log(x) = 3\]take away y from both sides .\[\log(x) = 3-y\]then applied log identity \[x = 10^{3-y}\]

  11. anonymous
    • one year ago
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    No I think I got it now! Thank you!

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