anonymous
  • anonymous
Y=3-logx How is this done??
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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UnkleRhaukus
  • UnkleRhaukus
Is that \[y = \log_3(x)\]? use the log identity \[y = \log_b(x)\qquad\iff\qquad b^y=x \]
anonymous
  • anonymous
Yeah I know that but how is it done with a negative between 3 and logx
anonymous
  • anonymous
the answer is y=10^3-y but how

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UnkleRhaukus
  • UnkleRhaukus
oh it is a negative? like this \[y = 3-\log(x)\]?
UnkleRhaukus
  • UnkleRhaukus
sorry for my earlier misinterpretation.
anonymous
  • anonymous
No its suppose to be a negative between the three and y
UnkleRhaukus
  • UnkleRhaukus
oh , right i erred \[y = 3 - \log (x)\\ \log(x) = 3-y\\ x = 10^{3-y}\]
UnkleRhaukus
  • UnkleRhaukus
Is this what you were looking for?
anonymous
  • anonymous
Wait so what exactly did you do?
UnkleRhaukus
  • UnkleRhaukus
\[y = 3 - \log (x)\]add log x to both sides of the equation, \[y+\log(x) = 3\]take away y from both sides .\[\log(x) = 3-y\]then applied log identity \[x = 10^{3-y}\]
anonymous
  • anonymous
No I think I got it now! Thank you!

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