anonymous
  • anonymous
Y=3-logx How is this done??
Mathematics
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anonymous
  • anonymous
Y=3-logx How is this done??
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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UnkleRhaukus
  • UnkleRhaukus
Is that \[y = \log_3(x)\]? use the log identity \[y = \log_b(x)\qquad\iff\qquad b^y=x \]
anonymous
  • anonymous
Yeah I know that but how is it done with a negative between 3 and logx
anonymous
  • anonymous
the answer is y=10^3-y but how

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UnkleRhaukus
  • UnkleRhaukus
oh it is a negative? like this \[y = 3-\log(x)\]?
UnkleRhaukus
  • UnkleRhaukus
sorry for my earlier misinterpretation.
anonymous
  • anonymous
No its suppose to be a negative between the three and y
UnkleRhaukus
  • UnkleRhaukus
oh , right i erred \[y = 3 - \log (x)\\ \log(x) = 3-y\\ x = 10^{3-y}\]
UnkleRhaukus
  • UnkleRhaukus
Is this what you were looking for?
anonymous
  • anonymous
Wait so what exactly did you do?
UnkleRhaukus
  • UnkleRhaukus
\[y = 3 - \log (x)\]add log x to both sides of the equation, \[y+\log(x) = 3\]take away y from both sides .\[\log(x) = 3-y\]then applied log identity \[x = 10^{3-y}\]
anonymous
  • anonymous
No I think I got it now! Thank you!

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