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## Knockknock one year ago Consider the function represented by the equation 1/2j+1/4k=3.Which shows the equation written in function notation with j as the independent variable

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1. anonymous

If j is the independent variable, you need to solve the equation for k.

2. anonymous

Is it just the 2 and 4 in the denominator, or are the j and k there too?

3. knockknock

I can give you the 4 options for it. F(j)=-2j+12 F(j)=-1/2j+6 F(k)=-2k+12 F(k)=-1/2k+6

4. anonymous

No, I meant what is the original equation? Which of these?$\frac{ 1 }{ 2 }j+\frac{ 1 }{ 4 }k=3$$\frac{ 1 }{ 2j }+\frac{ 1 }{ 4k }=3$

5. knockknock

My mistake it's the first one that you have (I can't write my equations like that for some reason)

6. knockknock

I just want to know how to start solving it so I can find out the answer

7. anonymous

Multiply by 4 to clear the fractions

8. anonymous

because it's the least common denominator

9. anonymous

|dw:1434732715187:dw|

10. anonymous

So solve that for k

11. knockknock

I got j=3/2 k=3 kinda lost on how to do this

12. anonymous

You're trying to get k by itself on one side of the equation. On the left side you have 2j added to k. So you need to subtract 2j from both sides to get k by itself

13. knockknock

Ohh okay now I have k=-2j+3

14. anonymous

right

15. anonymous

and to put it in function notation, just write k as k(j)

16. knockknock

Okay thanks :)

17. anonymous

actually you forgot to multiply the 4 and 3 on the right, so -2j+12

18. anonymous

@Knockknock

19. knockknock

Okay

20. knockknock

And j is the independent variable so would that mean it's -2j or -2k

21. knockknock

@peachpi

22. anonymous

it's -2j. k = f(j) = -2j +12

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