Knockknock
  • Knockknock
Consider the function represented by the equation 1/2j+1/4k=3.Which shows the equation written in function notation with j as the independent variable
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
If j is the independent variable, you need to solve the equation for k.
anonymous
  • anonymous
Is it just the 2 and 4 in the denominator, or are the j and k there too?
Knockknock
  • Knockknock
I can give you the 4 options for it. F(j)=-2j+12 F(j)=-1/2j+6 F(k)=-2k+12 F(k)=-1/2k+6

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anonymous
  • anonymous
No, I meant what is the original equation? Which of these?\[\frac{ 1 }{ 2 }j+\frac{ 1 }{ 4 }k=3\]\[\frac{ 1 }{ 2j }+\frac{ 1 }{ 4k }=3\]
Knockknock
  • Knockknock
My mistake it's the first one that you have (I can't write my equations like that for some reason)
Knockknock
  • Knockknock
I just want to know how to start solving it so I can find out the answer
anonymous
  • anonymous
Multiply by 4 to clear the fractions
anonymous
  • anonymous
because it's the least common denominator
anonymous
  • anonymous
|dw:1434732715187:dw|
anonymous
  • anonymous
So solve that for k
Knockknock
  • Knockknock
I got j=3/2 k=3 kinda lost on how to do this
anonymous
  • anonymous
You're trying to get k by itself on one side of the equation. On the left side you have 2j added to k. So you need to subtract 2j from both sides to get k by itself
Knockknock
  • Knockknock
Ohh okay now I have k=-2j+3
anonymous
  • anonymous
right
anonymous
  • anonymous
and to put it in function notation, just write k as k(j)
Knockknock
  • Knockknock
Okay thanks :)
anonymous
  • anonymous
actually you forgot to multiply the 4 and 3 on the right, so -2j+12
anonymous
  • anonymous
@Knockknock
Knockknock
  • Knockknock
Okay
Knockknock
  • Knockknock
And j is the independent variable so would that mean it's -2j or -2k
Knockknock
  • Knockknock
@peachpi
anonymous
  • anonymous
it's -2j. k = f(j) = -2j +12

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