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Knockknock
 one year ago
Consider the function represented by the equation 1/2j+1/4k=3.Which shows the equation written in function notation with j as the independent variable
Knockknock
 one year ago
Consider the function represented by the equation 1/2j+1/4k=3.Which shows the equation written in function notation with j as the independent variable

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If j is the independent variable, you need to solve the equation for k.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is it just the 2 and 4 in the denominator, or are the j and k there too?

knockknock
 one year ago
Best ResponseYou've already chosen the best response.0I can give you the 4 options for it. F(j)=2j+12 F(j)=1/2j+6 F(k)=2k+12 F(k)=1/2k+6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No, I meant what is the original equation? Which of these?\[\frac{ 1 }{ 2 }j+\frac{ 1 }{ 4 }k=3\]\[\frac{ 1 }{ 2j }+\frac{ 1 }{ 4k }=3\]

knockknock
 one year ago
Best ResponseYou've already chosen the best response.0My mistake it's the first one that you have (I can't write my equations like that for some reason)

knockknock
 one year ago
Best ResponseYou've already chosen the best response.0I just want to know how to start solving it so I can find out the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Multiply by 4 to clear the fractions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because it's the least common denominator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434732715187:dw

knockknock
 one year ago
Best ResponseYou've already chosen the best response.0I got j=3/2 k=3 kinda lost on how to do this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You're trying to get k by itself on one side of the equation. On the left side you have 2j added to k. So you need to subtract 2j from both sides to get k by itself

knockknock
 one year ago
Best ResponseYou've already chosen the best response.0Ohh okay now I have k=2j+3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and to put it in function notation, just write k as k(j)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0actually you forgot to multiply the 4 and 3 on the right, so 2j+12

knockknock
 one year ago
Best ResponseYou've already chosen the best response.0And j is the independent variable so would that mean it's 2j or 2k

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it's 2j. k = f(j) = 2j +12
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