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anonymous

  • one year ago

A quadratic equation is shown below: x^2 - 14x + 41 = 0 Which of the following is the first correct step to write the above equation in the form (x - p)^2 = q, where p and q are integers?

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  1. anonymous
    • one year ago
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    Add 8 to both sides of the equation Add 9 to both sides of the equation Subtract 8 from both sides of the equation Subtract 9 from both sides of the equation

  2. anonymous
    • one year ago
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    @welshfella

  3. welshfella
    • one year ago
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    Hint:- you need to make the left side a perfect square so the last term must be a perfect square

  4. welshfella
    • one year ago
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    - also when the trinomial is expanded the second term must be -14x

  5. anonymous
    • one year ago
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    add 8 to both sides?

  6. welshfella
    • one year ago
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    right - to give 49 as the last term on LHS which will also give the -14x

  7. anonymous
    • one year ago
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    thanks!

  8. welshfella
    • one year ago
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    yw

  9. anonymous
    • one year ago
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    can you help me with one more?

  10. welshfella
    • one year ago
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    ok

  11. anonymous
    • one year ago
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    What are the exact solutions of x^2 - 3x - 1 = 0?

  12. anonymous
    • one year ago
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  13. welshfella
    • one year ago
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    this is an exercise in completing the square first divide the coefficient of x ( that us the -3) by 2 and write x^2 - 3x - 1 = ( x - 1.5)^2 -2.25 - 1 = 0 the -2.25 comes from when you square -1.5 it becomes 2.25 so you have to subtract 2.25 to square things up

  14. welshfella
    • one year ago
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    so (x - 1.5)^2 = 3.25

  15. anonymous
    • one year ago
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    my answer was the first one

  16. welshfella
    • one year ago
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    Oh they want the answer as a fraction so i'll change it to fractions.

  17. welshfella
    • one year ago
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    lets check it....

  18. anonymous
    • one year ago
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    okay

  19. welshfella
    • one year ago
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    no i dont get that lets see x - 3/2 = +/- sqrt13/2 = 3/2 + sqrt13/2 or 3/2 - sqrt13/2 = 3 +/- sqrt13 ---------- 2

  20. anonymous
    • one year ago
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    so C?

  21. welshfella
    • one year ago
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    yes

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