A quadratic equation is shown below: x^2 - 14x + 41 = 0 Which of the following is the first correct step to write the above equation in the form (x - p)^2 = q, where p and q are integers?

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A quadratic equation is shown below: x^2 - 14x + 41 = 0 Which of the following is the first correct step to write the above equation in the form (x - p)^2 = q, where p and q are integers?

Mathematics
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Add 8 to both sides of the equation Add 9 to both sides of the equation Subtract 8 from both sides of the equation Subtract 9 from both sides of the equation
Hint:- you need to make the left side a perfect square so the last term must be a perfect square

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Other answers:

- also when the trinomial is expanded the second term must be -14x
add 8 to both sides?
right - to give 49 as the last term on LHS which will also give the -14x
thanks!
yw
can you help me with one more?
ok
What are the exact solutions of x^2 - 3x - 1 = 0?
this is an exercise in completing the square first divide the coefficient of x ( that us the -3) by 2 and write x^2 - 3x - 1 = ( x - 1.5)^2 -2.25 - 1 = 0 the -2.25 comes from when you square -1.5 it becomes 2.25 so you have to subtract 2.25 to square things up
so (x - 1.5)^2 = 3.25
my answer was the first one
Oh they want the answer as a fraction so i'll change it to fractions.
lets check it....
okay
no i dont get that lets see x - 3/2 = +/- sqrt13/2 = 3/2 + sqrt13/2 or 3/2 - sqrt13/2 = 3 +/- sqrt13 ---------- 2
so C?
yes

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