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anonymous

  • one year ago

Which statement is true? In any right triangle, the sine of one acute angle is equal to the cosine of the other acute angle. In any right triangle, the sine of one acute angle is equal to the sine of its complementary angle. In any right triangle, the cosine of one acute angle is equal to the cosine of its complementary angle. In any right triangle, the sum of the sine of one acute angle and the cosine of the other acute angle is 1.

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  1. anonymous
    • one year ago
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    D i think

  2. anonymous
    • one year ago
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    yea thanks man

  3. wolf1728
    • one year ago
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    No I don't think D sine 45 = .707 cosine 45 = .707 Sum does NOT = 1

  4. wolf1728
    • one year ago
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    sine 10 = .17365 cosine 80 = .17365 sum NOT = 1

  5. wolf1728
    • one year ago
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    Seems like it might be A Not sure

  6. wolf1728
    • one year ago
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    Anyone else care to give an answer?

  7. anonymous
    • one year ago
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    @wolf1728 is correct, it's A. Those are cofunction identities. \[\cos(90^o-\theta)=\sin \theta\] \[\sin(90^o-\theta)=\cos \theta\]

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