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anonymous
 one year ago
**Please Help Me**A solution is made by dissolving 15.5 grams of glucose (C6H12O6) in 245 grams of water. What is the freezingpoint depression of the solvent if the freezing point constant is 1.86 °C/m? Show all of the work needed to solve this problem.
anonymous
 one year ago
**Please Help Me**A solution is made by dissolving 15.5 grams of glucose (C6H12O6) in 245 grams of water. What is the freezingpoint depression of the solvent if the freezing point constant is 1.86 °C/m? Show all of the work needed to solve this problem.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@dan815 @Luigi0210 @zepdrix @welshfella @BTaylor @Cuanchi @Mehek14 @eyesac @aaronq

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@geny55 @sammixboo @omgitsjc @Cuanchi @jadaaaa

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@geny55 @pamela.g @radar @sammixboo @foreverthebeast @eyesac @Lokid @Luigi0210 @Mertsj @MrNood @Crazypizzalover @Xaze @Megaforte8600 @razor99 @sleepyjess

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1use the formula \(\Delta T=i*m*K_f\) where \(\Delta T\) is the change in temp from the pure solvent's f.p. i is the van't hoff constant, 1 in the case for sugar m is the molality of the solution \\(K_f\) is the f.p. depression constant

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait don't we got to find the morality first @aaronq

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you setup how to find the moles for me

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1divide the mass by the molar mass of glucose (which is 180 g/mol)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So that is the freezing point

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1idk, it mean it sounds right. you found moles, then molality, then multiplied by the constant? if so, then it should be right.
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