anonymous
  • anonymous
**Please Help Me**A solution is made by dissolving 15.5 grams of glucose (C6H12O6) in 245 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m? Show all of the work needed to solve this problem.
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@dan815 @Luigi0210 @zepdrix @welshfella @BTaylor @Cuanchi @Mehek14 @eyesac @aaronq
anonymous
  • anonymous
@sweetburger
anonymous
  • anonymous
@beckie29

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anonymous
  • anonymous
@geny55 @sammixboo @omgitsjc @Cuanchi @jadaaaa
anonymous
  • anonymous
@geny55 @pamela.g @radar @sammixboo @foreverthebeast @eyesac @Lokid @Luigi0210 @Mertsj @MrNood @Crazypizzalover @Xaze @Megaforte8600 @razor99 @sleepyjess
aaronq
  • aaronq
use the formula \(\Delta T=i*m*K_f\) where \(\Delta T\) is the change in temp from the pure solvent's f.p. i is the van't hoff constant, 1 in the case for sugar m is the molality of the solution \\(K_f\) is the f.p. depression constant
anonymous
  • anonymous
wait don't we got to find the morality first @aaronq
aaronq
  • aaronq
yup
aaronq
  • aaronq
then use the formula
anonymous
  • anonymous
Can you setup how to find the moles for me
anonymous
  • anonymous
@aaronq
aaronq
  • aaronq
divide the mass by the molar mass of glucose (which is 180 g/mol)
anonymous
  • anonymous
Ok I have 0.15996
anonymous
  • anonymous
-0.15996* @aaronq
aaronq
  • aaronq
what is that?
anonymous
  • anonymous
Delta T @aaronq
aaronq
  • aaronq
alright
anonymous
  • anonymous
So that is the freezing point
anonymous
  • anonymous
@aaronq
aaronq
  • aaronq
idk, it mean it sounds right. you found moles, then molality, then multiplied by the constant? if so, then it should be right.

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