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mathmath333
 one year ago
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mathmath333
 one year ago
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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align} &\normalsize \text{if } x \normalsize \text{ is such that }\ 36\leq x\leq 72,\ \normalsize \text{then }\hspace{.33em}\\~\\ &y=\dfrac{x^2+2\sqrt x (x+4) +16}{x+4\sqrt x + 4} \hspace{.33em}\\~\\~\\ &a.) \ 20<y<54 \hspace{.33em}\\~\\ &b.) \ 23<y<58 \hspace{.33em}\\~\\ &c.) \ 25<y<64 \hspace{.33em}\\~\\ &d.) \ 28<y<60 \hspace{.33em}\\~\\ \end{align}}\)

Rizags
 one year ago
Best ResponseYou've already chosen the best response.1just evaluate y at the upper and lower bounds of x

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0but putting the limits initially seems a pain there should be some simplification for this before putting the limits

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1dw:1434748584586:dw maybe I can try?

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1dw:1434748759962:dw

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1dw:1434748873145:dw
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