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anonymous

  • one year ago

I will give a medal. Please explain how to do it not just the answer, thanks! Solve x^2 - 3x = -8.

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  1. misty1212
    • one year ago
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    HI!!

  2. anonymous
    • one year ago
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    Hello.

  3. misty1212
    • one year ago
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    add 8 and solve \[x^2-3x+8=0\] using the quadratic formula \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with \[a=1,b=-3,c=8\] there will be no real solutions, but two complex ones

  4. anonymous
    • one year ago
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    So would \[x=3+-i \sqrt{23}/2\] be correct?

  5. anonymous
    • one year ago
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    @misty1212

  6. Loser66
    • one year ago
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    yes, but the real part is 3/2, not just 3

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