anonymous
  • anonymous
PLEASE HELP ME I WILL MEDAL AND FAN I DONT WANT AN ANSWER. SCROLL DOWN ALL THE WAY, I STILL NEED HELP Bruce has a bottle that contains 60% of lemon juice and the rest water. The bottle has 1 liter of water. Part A: Write an equation in one variable that can be used to find the total number of liters of lemon juice and water in the bottle. Define the variable used in the equation. Part B: How many liters of lemon juice are present in the bottle? Show your work.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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misty1212
  • misty1212
HI!!
misty1212
  • misty1212
the total number of liters of water is not something you have to find, it is 1 liter what you have to find is the liters of lemon juice name a variable, and say that it represents the number of liters of lemon juice
anonymous
  • anonymous
j=lemon juice

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More answers

misty1212
  • misty1212
what do you want to call your variable? ok J = liters of lemon juice, fine
anonymous
  • anonymous
t= total amount of juice
misty1212
  • misty1212
you don't need two variables, one will do
misty1212
  • misty1212
especially since it says "Write an equation in ONE variable "
anonymous
  • anonymous
ok, but we have to find the total of lemon juice and water, not just lemon juice, so i didnt knoe...
misty1212
  • misty1212
if J is the amount of lemon juice and there is one liter of water, then the total amount is \[J+1\] which is why you don't need another variable
anonymous
  • anonymous
ok
misty1212
  • misty1212
then \(60\%\) of the total is lemon juice, the total is \(J+1\) so you can write an equation \[J=0.6\times (J+1)\] and solve that for \(J\)
misty1212
  • misty1212
if you do it correctly you should get \(J=1.5\)
anonymous
  • anonymous
ok so first I would subtract?
anonymous
  • anonymous
because I need to do the work
anonymous
  • anonymous
please help
sdfgsdfgs
  • sdfgsdfgs
Like @misty1212 said, "J=0.6×(J+1) and solve that for J" First step is J=0.6J+0.6 OK?
anonymous
  • anonymous
okk?
sdfgsdfgs
  • sdfgsdfgs
What do you think the next step is then?
anonymous
  • anonymous
subtract 1?
anonymous
  • anonymous
@sdfgsdfgs
sdfgsdfgs
  • sdfgsdfgs
no, group all terms with the variable J on to one side....
anonymous
  • anonymous
?ok.. how do i do that
sdfgsdfgs
  • sdfgsdfgs
J=0.6J+0.6 so which term includes the variable J
anonymous
  • anonymous
0.6j? @sdfgsdfgs
sdfgsdfgs
  • sdfgsdfgs
And J on the left hand side! Move them all to one side but subtracting 0.6J
anonymous
  • anonymous
ok
sdfgsdfgs
  • sdfgsdfgs
What do you get after that?
anonymous
  • anonymous
j=.6?
anonymous
  • anonymous
@sdfgsdfgs
anonymous
  • anonymous
please?
sdfgsdfgs
  • sdfgsdfgs
J=0.6J+0.6 subtract 0.6J on the left and right hand side
anonymous
  • anonymous
j-6j=.6
sdfgsdfgs
  • sdfgsdfgs
what is the left side equal to?
anonymous
  • anonymous
0.6?
sdfgsdfgs
  • sdfgsdfgs
That is the right side. how about the left?
anonymous
  • anonymous
j-.6j
sdfgsdfgs
  • sdfgsdfgs
what is that equal to?
anonymous
  • anonymous
.6
anonymous
  • anonymous
@sdfgsdfgs
anonymous
  • anonymous
@myininaya
anonymous
  • anonymous
@sdfgsdfgs

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