Part A: Divide (8x4y3 + 4x3y2 - 2x2y - 12x2y4) by -2x2y. Show your work, and justify each step. (6 points) Part B: How would your answer in Part A be affected if the x2 variable in the denominator was just an x? (2 points) Part C: What is the degree and classification of the polynomial you got in Part A? (2 points)

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Part A: Divide (8x4y3 + 4x3y2 - 2x2y - 12x2y4) by -2x2y. Show your work, and justify each step. (6 points) Part B: How would your answer in Part A be affected if the x2 variable in the denominator was just an x? (2 points) Part C: What is the degree and classification of the polynomial you got in Part A? (2 points)

Algebra
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\[\frac{ 8x4y^3+4x3y^2-2x2y-12x2y^4}{ -2x2y}\] Do you know what to do here?
yes you have to divide it
i just do not know how to divide something so big

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Other answers:

can you plz help
yes i guess so
It's actually quite simple. Start with the first part they give you and and divide it by -2x2y So that gives you: \[\frac{ 8x4y^3 }{ -2x2y }\] So 8x/-2x, would be -4. Now 4y^3/2y would be 2y^2. Then you would have to multiply -4(2y^2), giving you -8y^2 for the first part
Do you understand how I got that for the first part of the equation?
yes
Okay, now do the same for every other part of the equation
OH MY GOD PEOPLE USE TO GIVE THE ANSWERS NOW THEY ARE ONLY HELPING YOU I AM RUNNING AGAINST THE CLOCK
NOW ONE HAS HELPED ME FOR 2 HOURS NOW MY QUIZ IS GOING TO LOSE ALL THE INFO
ALRIGHT SASSY. \[6y^3-8y^2-3y\] is your answer

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