HelloKitty17
  • HelloKitty17
Part A: Divide (8x4y3 + 4x3y2 - 2x2y - 12x2y4) by -2x2y. Show your work, and justify each step. (6 points) Part B: How would your answer in Part A be affected if the x2 variable in the denominator was just an x? (2 points) Part C: What is the degree and classification of the polynomial you got in Part A? (2 points)
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\frac{ 8x4y^3+4x3y^2-2x2y-12x2y^4}{ -2x2y}\] Do you know what to do here?
OregonDuck
  • OregonDuck
yes you have to divide it
OregonDuck
  • OregonDuck
i just do not know how to divide something so big

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OregonDuck
  • OregonDuck
can you plz help
OregonDuck
  • OregonDuck
@LegendarySadist @mathmate @welshfella
OregonDuck
  • OregonDuck
yes i guess so
OregonDuck
  • OregonDuck
@Aureyliant
anonymous
  • anonymous
It's actually quite simple. Start with the first part they give you and and divide it by -2x2y So that gives you: \[\frac{ 8x4y^3 }{ -2x2y }\] So 8x/-2x, would be -4. Now 4y^3/2y would be 2y^2. Then you would have to multiply -4(2y^2), giving you -8y^2 for the first part
anonymous
  • anonymous
Do you understand how I got that for the first part of the equation?
OregonDuck
  • OregonDuck
yes
anonymous
  • anonymous
Okay, now do the same for every other part of the equation
OregonDuck
  • OregonDuck
OH MY GOD PEOPLE USE TO GIVE THE ANSWERS NOW THEY ARE ONLY HELPING YOU I AM RUNNING AGAINST THE CLOCK
OregonDuck
  • OregonDuck
NOW ONE HAS HELPED ME FOR 2 HOURS NOW MY QUIZ IS GOING TO LOSE ALL THE INFO
anonymous
  • anonymous
ALRIGHT SASSY. \[6y^3-8y^2-3y\] is your answer

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