A chemist needs 190 milliliters of a 47% solution but has only 25% and 63% solutions available. Find how many milliliters of each that should be mixed to get the desired solution.

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A chemist needs 190 milliliters of a 47% solution but has only 25% and 63% solutions available. Find how many milliliters of each that should be mixed to get the desired solution.

Mathematics
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If we assume that x = number of milliliters of 25% solution y = number of milliliters of 63% solution x + y = 190 .25x + .63y = 190 * .47
Okay
I match up the y's to cancel them out correct?

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yes, you can solve by substitution or elimination
I got x=317.38 which cant be correct
x + y = 190 .25x + .63y = 190 * .47 multiply the second equation by 100. that will get rid of decimals. x+y=190 25x + 63y = 8930
x=-230 then I plug this into x+y=190
x should be positive
Yes ... For x+y=190 times it all by -63 to cancel out the ys ... But then I get -38x=8740
Did you get this? -63x -63y = -11970 25x + 63y = 8930
I multiplied first equation by -63
-.- oh my gosh i left it as -190
:D
x=80 and y=110
Thank you!

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