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saucvi

  • one year ago

A sequence has its first term equal to 4, and each term of the sequence is obtained by adding 2 to the previous term. If f(n) represents the nth term of the sequence, which of the following recursive functions best defines this sequence?

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  1. saucvi
    • one year ago
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    A. f(1)=2 and f(n) = f(n-1)+4; n>1 B. f(1) =4 and f(n) = f(n-1)+2n; n>1 C. f(1) =2 and f(n) = f(n-1) +4n; n>1 D. f(1)=4 and f(n) = f(n-1) + 2; n >1 If you could please explain how to get the answer that would be a big help because I have no idea where to even start.

  2. anonymous
    • one year ago
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    f(1) is the first term, so f(1) = 4. The nth term is f(n), so the previous term would be f(n-1). For example, n = 6 for the sixth term, which is f(6). The term before that is the fifth term, f(5), which is the same as f(6 - 1).

  3. anonymous
    • one year ago
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    To get each f(n) you need to add 2 to f(n - 1), so f(n) = f(n -1) + 2

  4. saucvi
    • one year ago
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    @peachpi so would the answer be B?

  5. anonymous
    • one year ago
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    no. not +2n, just +2

  6. saucvi
    • one year ago
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    OH. I think I get it now. Thank you so much.

  7. anonymous
    • one year ago
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    you're welcome

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