anonymous
  • anonymous
A parallelogram whose vertices have coordinates R(1, -1), S(6, 1), T(8, 5), and U(3, 3) has a shorter diagonal of ___ . 5 √(13) √(97)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@perl can you please help??
perl
  • perl
one moment
anonymous
  • anonymous
Thank you!!

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perl
  • perl
I plotted the points here
perl
  • perl
thats the short diagonal http://prntscr.com/7izzgt
anonymous
  • anonymous
So would it be 5?
perl
  • perl
we want the distance between (3,3) and (6,1) distance = \( \sqrt{ (6-3)^2 + (1-3)^2} = \sqrt{ 9 + 4} = \sqrt{13}\)
anonymous
  • anonymous
Ugh. I did it wrong, Thank you for helping me! If I have any more can you help me?
perl
  • perl
ok :)

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