anonymous one year ago A parallelogram whose vertices have coordinates R(1, -1), S(6, 1), T(8, 5), and U(3, 3) has a shorter diagonal of ___ . 5 √(13) √(97)

1. anonymous

2. perl

one moment

3. anonymous

Thank you!!

4. perl

I plotted the points here

5. perl

thats the short diagonal http://prntscr.com/7izzgt

6. anonymous

So would it be 5?

7. perl

we want the distance between (3,3) and (6,1) distance = $$\sqrt{ (6-3)^2 + (1-3)^2} = \sqrt{ 9 + 4} = \sqrt{13}$$

8. anonymous

Ugh. I did it wrong, Thank you for helping me! If I have any more can you help me?

9. perl

ok :)