anonymous
  • anonymous
The number of years, N(r), since two independently evolving languages split off from a common ancestral language is approximated by N(r)=-5000 In (r), where r is the percent of words from the ancestral language common to both languages. Find N if r=80%
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
I know how to set it up. It should look like N(r)=-5000 In (.80) Though I am not sure what In stands for because my homework doesn't tell me. There is an example that my homework gave me if you would like me to write it down really fast and I can't figure out where they got their answer.
perl
  • perl
ln stands for the natural logarithm
anonymous
  • anonymous
oh! what is the natural log?

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More answers

perl
  • perl
ln(1) means the same as \(\large \log_e(1) \)
perl
  • perl
It is the logarithm with a base of a special constant \(\large e = 2.71818...\)
anonymous
  • anonymous
\[ e^{\ln x} = x \\ \ln(e^x) = x\\ \ln(x) = \log_e(x) \]
anonymous
  • anonymous
Though \(e^{\ln(x)}\) requires that \(x>0\).
anonymous
  • anonymous
oh ok! so it should be N(r)=-5000(2.718181)(.80)
perl
  • perl
\( \Large N(r)=-5000 \log_e (r)\) That decimal e=2.71828... never ends so its easier to just label it as e
anonymous
  • anonymous
how do I type that into the calculator? I have a TI-84 C
perl
  • perl
since r is a percent you want r / 100 80% = .80 \( \Large N(.80)=-5000 \log_e (.80)\) There should be an LN button on your calculator
perl
  • perl
-5000 ln(.80)
anonymous
  • anonymous
I know you press 2nd then the LN button but I don't know what to type in there after I press those buttons
perl
  • perl
you don't need to press 2nd LN
anonymous
  • anonymous
Oh I got it thanks!
perl
  • perl
2nd LN is e^x , a different function
anonymous
  • anonymous
so the answer should be 1115.7178 and when we round it to the nearest whole number it should be 1116 right?
anonymous
  • anonymous
is that right?
perl
  • perl
yes
anonymous
  • anonymous
awesome, thank you for your help!

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