anonymous
  • anonymous
The width of a rectangle is 12 units. Can the perimeter x of the rectangle can be 60 units when its length y is 18 units? A:No, the rectangle cannot have x = 60 and y = 18 because x + y is less than 60 B:No, the rectangle cannot have x = 60 and y = 18 because x + y is less than 24 C:Yes, the rectangle can have x = 60 and y = 18 because x = 12 + 2y D:Yes, the rectangle can have x = 60 and y = 18 because x = 24 + 2y
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
anonymous
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anonymous
  • anonymous

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anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
@Mehek14 can you help me please
Mehek14
  • Mehek14
|dw:1434755438008:dw|
Mehek14
  • Mehek14
so add up 18+18+12+12 to find the perimeter
anonymous
  • anonymous
60
Mehek14
  • Mehek14
correct so the perimeter can be 60
Mehek14
  • Mehek14
that means that you can eliminate A and B
anonymous
  • anonymous
ok
Mehek14
  • Mehek14
now the formula for perimeter is P = 2w + 2l w = width l = length
Mehek14
  • Mehek14
in your case length is y so P = 2w + 2y
Mehek14
  • Mehek14
you know that the width is 12 so P = 2(12) + 2y 2*12 = 24
Mehek14
  • Mehek14
so your formula would be x = 24 + 2y
anonymous
  • anonymous
So D
Mehek14
  • Mehek14
yes
anonymous
  • anonymous
Can you help with one more
Mehek14
  • Mehek14
sure
anonymous
  • anonymous
ill open a new question so u can get another medal
Mehek14
  • Mehek14
alright thanks

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