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anonymous

  • one year ago

The width of a rectangle is 12 units. Can the perimeter x of the rectangle can be 60 units when its length y is 18 units? A:No, the rectangle cannot have x = 60 and y = 18 because x + y is less than 60 B:No, the rectangle cannot have x = 60 and y = 18 because x + y is less than 24 C:Yes, the rectangle can have x = 60 and y = 18 because x = 12 + 2y D:Yes, the rectangle can have x = 60 and y = 18 because x = 24 + 2y

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  1. anonymous
    • one year ago
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    @perl @dan815 @wio

  2. anonymous
    • one year ago
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    @mathmath333

  3. anonymous
    • one year ago
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    @Hero

  4. anonymous
    • one year ago
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    @hughfuve

  5. anonymous
    • one year ago
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    @Hero @mathmath333 @perl @dan815 @wio

  6. anonymous
    • one year ago
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    @Mehek14 can you help me please

  7. Mehek14
    • one year ago
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    |dw:1434755438008:dw|

  8. Mehek14
    • one year ago
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    so add up 18+18+12+12 to find the perimeter

  9. anonymous
    • one year ago
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    60

  10. Mehek14
    • one year ago
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    correct so the perimeter can be 60

  11. Mehek14
    • one year ago
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    that means that you can eliminate A and B

  12. anonymous
    • one year ago
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    ok

  13. Mehek14
    • one year ago
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    now the formula for perimeter is P = 2w + 2l w = width l = length

  14. Mehek14
    • one year ago
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    in your case length is y so P = 2w + 2y

  15. Mehek14
    • one year ago
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    you know that the width is 12 so P = 2(12) + 2y 2*12 = 24

  16. Mehek14
    • one year ago
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    so your formula would be x = 24 + 2y

  17. anonymous
    • one year ago
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    So D

  18. Mehek14
    • one year ago
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    yes

  19. anonymous
    • one year ago
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    Can you help with one more

  20. Mehek14
    • one year ago
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    sure

  21. anonymous
    • one year ago
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    ill open a new question so u can get another medal

  22. Mehek14
    • one year ago
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    alright thanks

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