anonymous
  • anonymous
Can someone tell me how you factor this for a medal?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Factor 3x^2y^2 - 2xy^2 - 8y^2
anonymous
  • anonymous
(x+2y)(3x-4y)
MrNood
  • MrNood
that is not correct the first expansion of that would give 3x^ as a term - but there is no such term in the expression

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MrNood
  • MrNood
@ImaGuest This is a good reason why you should not accept direct answers You have no idea of the competence of those answering - MANY answers here are just WRONG
Plasmataco
  • Plasmataco
lol
anonymous
  • anonymous
I know, thats why I said "tell me how you factor...". I usually don't accept direct answers anyways :)
Plasmataco
  • Plasmataco
are you sure there is a 3x^2y^2?
MrNood
  • MrNood
\[3x ^{2}y ^{2} - 2xy ^{2} - 8y ^{2}\]
Plasmataco
  • Plasmataco
because that is kinda complicated...
Plasmataco
  • Plasmataco
ohhhhh.
Plasmataco
  • Plasmataco
well. what do you do first?
Plasmataco
  • Plasmataco
there is y^2 in every term, so you can factor that out.
MrNood
  • MrNood
To be a factor - the values have to appear in every term you can see y^2 is in every term - so start by making that a factor
anonymous
  • anonymous
Yeah, I'm positive.
Plasmataco
  • Plasmataco
you will get y^2(3x^2-2x-8)
Plasmataco
  • Plasmataco
now. how do you factor 3x^2-2x-8?
MrNood
  • MrNood
@Plasmataco you should let @ImaGuest do the work 0 it's his question
anonymous
  • anonymous
@MrNood I would if I could, and if I could I wouldn't be on this site.
anonymous
  • anonymous
I wouldn't have made this thread if I knew what to do
Plasmataco
  • Plasmataco
(3x+4)(x-2)
Plasmataco
  • Plasmataco
so, your answer would be y^2(3x+4)(x-2)
anonymous
  • anonymous
Ok but I want to know how to factor this.
Plasmataco
  • Plasmataco
ok.
anonymous
  • anonymous
A direct answer is fine, but I need to show my work
Plasmataco
  • Plasmataco
I know. I'll explain.
anonymous
  • anonymous
And if you could walk me through it, I would appreciate it
Plasmataco
  • Plasmataco
when you factor a ax^2+bx+c,
Plasmataco
  • Plasmataco
waaaait. im explaining, I like to give the answer, then explain.
MrNood
  • MrNood
you have the answer above y^2 (3x+4)(x-2) now try the next similar question
MrNood
  • MrNood
9 out of 10 posters will leave as soon as you give th eanswer
Plasmataco
  • Plasmataco
when you factor, you look at a. if it's 1, you automatically get into a format of (x+?)(x+?)
anonymous
  • anonymous
Well I didn't leave. What does that make me?
Plasmataco
  • Plasmataco
? wat, im talking to Mr.nood
Plasmataco
  • Plasmataco
understand so far?
MrNood
  • MrNood
you didn't explain yet about taking y^2 out as a factor
Plasmataco
  • Plasmataco
ok. when every term has a common factor, you can bring it out.
Plasmataco
  • Plasmataco
say you have 2y-4, 2 is a common factor, therefore, you can say 2(y-2)
Plasmataco
  • Plasmataco
got it?
Plasmataco
  • Plasmataco
now. back to the second part...
MrNood
  • MrNood
so what are you left with when you take y^2 from the original equation @ImaGuest ?
anonymous
  • anonymous
Nah, Im still here. Sorry, someone was at the door.
Plasmataco
  • Plasmataco
its fine, look above. do you get it so far?
anonymous
  • anonymous
Yeah, so far I do.
Plasmataco
  • Plasmataco
ok. whenever you factor with something like the second part, you always want to end up like (ax+b)(cx+d), a and c can be one.
Plasmataco
  • Plasmataco
I'll give you an example, that's the easiest way to teach you.
anonymous
  • anonymous
Alright
Plasmataco
  • Plasmataco
when you factor Y^2+3Y+2, you factor into (Y+2)(Y+1).
Plasmataco
  • Plasmataco
notice how 1*1=1 in the first term, 1+2=3, in the middle term and 1*2=2 in the third term
Plasmataco
  • Plasmataco
that's how you want to factor every thing, it's like a puzzle.
Plasmataco
  • Plasmataco
hello?
anonymous
  • anonymous
I'm here.
Plasmataco
  • Plasmataco
ok. look above.
Plasmataco
  • Plasmataco
see if you get it.
anonymous
  • anonymous
Yeah, I just finished reading them literally a few seconds before you said "hello?"
Plasmataco
  • Plasmataco
you get it?
anonymous
  • anonymous
Yeah I do. Thanks, you were of big help!
Plasmataco
  • Plasmataco
no problem.

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