Can someone tell me how you factor this for a medal?

- anonymous

Can someone tell me how you factor this for a medal?

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- anonymous

Factor 3x^2y^2 - 2xy^2 - 8y^2

- anonymous

(x+2y)(3x-4y)

- MrNood

that is not correct
the first expansion of that would give 3x^ as a term - but there is no such term in the expression

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## More answers

- MrNood

@ImaGuest This is a good reason why you should not accept direct answers
You have no idea of the competence of those answering - MANY answers here are just WRONG

- Plasmataco

lol

- anonymous

I know, thats why I said "tell me how you factor...". I usually don't accept direct answers anyways :)

- Plasmataco

are you sure there is a 3x^2y^2?

- MrNood

\[3x ^{2}y ^{2} - 2xy ^{2} - 8y ^{2}\]

- Plasmataco

because that is kinda complicated...

- Plasmataco

ohhhhh.

- Plasmataco

well. what do you do first?

- Plasmataco

there is y^2 in every term, so you can factor that out.

- MrNood

To be a factor - the values have to appear in every term
you can see y^2 is in every term - so start by making that a factor

- anonymous

Yeah, I'm positive.

- Plasmataco

you will get y^2(3x^2-2x-8)

- Plasmataco

now. how do you factor 3x^2-2x-8?

- MrNood

@Plasmataco
you should let @ImaGuest do the work 0 it's his question

- anonymous

@MrNood I would if I could, and if I could I wouldn't be on this site.

- anonymous

I wouldn't have made this thread if I knew what to do

- Plasmataco

(3x+4)(x-2)

- Plasmataco

so, your answer would be y^2(3x+4)(x-2)

- anonymous

Ok but I want to know how to factor this.

- Plasmataco

ok.

- anonymous

A direct answer is fine, but I need to show my work

- Plasmataco

I know. I'll explain.

- anonymous

And if you could walk me through it, I would appreciate it

- Plasmataco

when you factor a ax^2+bx+c,

- Plasmataco

waaaait. im explaining, I like to give the answer, then explain.

- MrNood

you have the answer above y^2 (3x+4)(x-2)
now try the next similar question

- MrNood

9 out of 10 posters will leave as soon as you give th eanswer

- Plasmataco

when you factor, you look at a. if it's 1, you automatically get into a format of (x+?)(x+?)

- anonymous

Well I didn't leave. What does that make me?

- Plasmataco

? wat, im talking to Mr.nood

- Plasmataco

understand so far?

- MrNood

you didn't explain yet about taking y^2 out as a factor

- Plasmataco

ok. when every term has a common factor, you can bring it out.

- Plasmataco

say you have 2y-4, 2 is a common factor, therefore, you can say 2(y-2)

- Plasmataco

got it?

- Plasmataco

now. back to the second part...

- MrNood

so what are you left with when you take y^2 from the original equation @ImaGuest ?

- anonymous

Nah, Im still here. Sorry, someone was at the door.

- Plasmataco

its fine, look above. do you get it so far?

- anonymous

Yeah, so far I do.

- Plasmataco

ok. whenever you factor with something like the second part, you always want to end up like (ax+b)(cx+d), a and c can be one.

- Plasmataco

I'll give you an example, that's the easiest way to teach you.

- anonymous

Alright

- Plasmataco

when you factor Y^2+3Y+2, you factor into (Y+2)(Y+1).

- Plasmataco

notice how 1*1=1 in the first term, 1+2=3, in the middle term and 1*2=2 in the third term

- Plasmataco

that's how you want to factor every thing, it's like a puzzle.

- Plasmataco

hello?

- anonymous

I'm here.

- Plasmataco

ok. look above.

- Plasmataco

see if you get it.

- anonymous

Yeah, I just finished reading them literally a few seconds before you said "hello?"

- Plasmataco

you get it?

- anonymous

Yeah I do. Thanks, you were of big help!

- Plasmataco

no problem.

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