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anonymous

  • one year ago

Find the equation of the circle whose center and radius are given. center ( 5, 6), radius = 3 This is how it's set up (X___________=_

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  1. anonymous
    • one year ago
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    @perl please help

  2. Plasmataco
    • one year ago
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    (X-5)^2+(Y-6)^2=3^2

  3. Plasmataco
    • one year ago
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    ???

  4. Plasmataco
    • one year ago
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    Is it correct?

  5. anonymous
    • one year ago
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    I don't know. I don't understand how to do this type of problem

  6. Loser66
    • one year ago
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    @Plasmataco Please, explain him how to get it. It is better than giving out the free answer.

  7. Loser66
    • one year ago
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    @Jcameron want to know how to get it?

  8. anonymous
    • one year ago
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    Yeah because I don't understand how you got that.

  9. anonymous
    • one year ago
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    @Loser66 Yes, or else I don't learn lol

  10. Loser66
    • one year ago
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    center is (h, k) , so tell me , the given center is (5,6) hence h =?? and k =??

  11. anonymous
    • one year ago
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    H= 5 K=6 ?

  12. Loser66
    • one year ago
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    yup, and radius =??

  13. anonymous
    • one year ago
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    Is 3^2?

  14. Loser66
    • one year ago
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    nope, just 3, they give you radius =3, how can you get 3^2

  15. Loser66
    • one year ago
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    ok?

  16. anonymous
    • one year ago
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    Oh sorry, I made a mistake. I was thinking about something different.

  17. anonymous
    • one year ago
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    Okay. So, how do I put that into an equation?

  18. Loser66
    • one year ago
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    \(\color{red}{h =5}\), \(\color{blue}{k=6}\), \(\color {orange}{radius =3}\) Formula of a circle is \((x -\color{red}{h})^2+(y-\color{blue}{k})^2=\color{orange}{radius^2}\)

  19. Loser66
    • one year ago
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    Plug the number in, pppppplease

  20. anonymous
    • one year ago
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    (x-5)^2+(y-6)^2=3^2 ?

  21. Loser66
    • one year ago
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    yyyyyyyyyyyyyup

  22. anonymous
    • one year ago
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    Thank you!

  23. Loser66
    • one year ago
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    np

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