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anonymous
 one year ago
Can anyone explain questions 2 and 3 on problem set 2?
Problem Set 
http://ocw.mit.edu/courses/mathematics/1802scmultivariablecalculusfall2010/1.vectorsandmatrices/partbmatricesandsystemsofequations/problemset2/MIT18_02SC_pset2.pdf
Problem Set Solutions 
http://ocw.mit.edu/courses/mathematics/1802scmultivariablecalculusfall2010/1.vectorsandmatrices/partbmatricesandsystemsofequations/problemset2/MIT18_02SC_pset2sol.pdf
anonymous
 one year ago
Can anyone explain questions 2 and 3 on problem set 2? Problem Set  http://ocw.mit.edu/courses/mathematics/1802scmultivariablecalculusfall2010/1.vectorsandmatrices/partbmatricesandsystemsofequations/problemset2/MIT18_02SC_pset2.pdf Problem Set Solutions  http://ocw.mit.edu/courses/mathematics/1802scmultivariablecalculusfall2010/1.vectorsandmatrices/partbmatricesandsystemsofequations/problemset2/MIT18_02SC_pset2sol.pdf

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For problem 2, Lets assume we have produced p1 units of P1, p2 units of P2 and p3 units of p3. Given the ratios, to produce p1 units of P1, we need (1/6)p1 units of M1, (1/3)p1 units of M2 and (1/2)p1 units of M3, and so on for P1 and P2. Now, if we are to look at the total amount of units of M1 used, we find that it is (1/6)p1 units + (1/9)p2 units + (3/16)p3 units. This quantity is equal to 137. So we can write the euqation (1/6)p1 + (1/9)p2 + (3/16)p3 = 137. Similarly, if we track the amount of M2 and M3 used, we get the following equations (1/3)p1 + (1/3)p2 +(5/16)p3 = 279 (1/2)p1 + (5/9)p2 + (1/2)p3 = 448 We can represent these three equations in the matrix form as \[\left[\begin{matrix}1/6 & 1/9&3/16 \\ 1/3 & 1/3&5/16\\1/2&5/9&1/2\end{matrix}\right]\left(\begin{matrix}p1 \\ p2\\p3\end{matrix}\right)=\left(\begin{matrix}137 \\ 279\\448\end{matrix}\right)\] Then you solve from there, by finding the inverse of the matrix etc as stated in the solution

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That was my reasoning of the problem. I hope it makes sense :)

phi
 one year ago
Best ResponseYou've already chosen the best response.0I am not sure this will help... it depends on exactly what your question is.
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