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anonymous
 one year ago
According to records, the amount of precipitation in a certain city on a November day has a mean of .1 inches, with a standard deviation of .6 inches. What is the probability that the mean daily precipitation will be .098 inches or more for a random sample of 40 November days (taken over many years)?
anonymous
 one year ago
According to records, the amount of precipitation in a certain city on a November day has a mean of .1 inches, with a standard deviation of .6 inches. What is the probability that the mean daily precipitation will be .098 inches or more for a random sample of 40 November days (taken over many years)?

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DebbieG
 one year ago
Best ResponseYou've already chosen the best response.1This is asking about a probability related to a SAMPLE MEAN, not just a data value. Thuse, you need to use the Central Limit Theorem formula to get the zscore: \[\large z=\frac{ \bar{x} \mu}{ \frac{ \sigma }{ \sqrt{n}} }\] You have \[\bar{x}=0.098\]\[\mu=0.1\]\[\sigma=0.6\]and n = 40. Compute the zscore, then use a normal table (or a calculator) to find the area to the right of the zscore.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i get an answer of 0.021

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait thats just the z score right?

DebbieG
 one year ago
Best ResponseYou've already chosen the best response.1Yes. And you should have gotten z=0.021, since xbar<mu. So now you need the standard normal probability for z>0.021.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so on the calculator i would just do P(Z<=.021) correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or would it be 1  that?

DebbieG
 one year ago
Best ResponseYou've already chosen the best response.1What is the probability that the mean daily precipitation will be .098 inches OR MORE... so you want the P(Z>0.021)  correct, you can get the area to the left, and subtract from 1. Or get the area to the right.

DebbieG
 one year ago
Best ResponseYou've already chosen the best response.1Or, if you understand how to take advantage of the symmetry of the distribution, you can even use P(Z<0.021) which is = P(Z>0.021). :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0awesome I think i am following you
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