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anonymous

  • one year ago

Find the following measure for this figure. Area of the base = 8 square units 16 square units 64 square units I believe the answer is 8 but I'm not quite sure

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    I just need to know if I'm right and if I'm wrong someone please explain how I'm wrong.

  3. DebbieG
    • one year ago
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    You're looking for the base of the cylinder? That's a circle, so the formula for area is A=pi*r^2

  4. DebbieG
    • one year ago
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    Maybe I'm misunderstanding the question, but as I read it, none of the answers you posted are correct, since none include pi.

  5. anonymous
    • one year ago
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    They do but I don't know how to put pi?

  6. anonymous
    • one year ago
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    So it's 16 pi?

  7. anonymous
    • one year ago
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    I thought it was the radius multiplied by height * pi

  8. DebbieG
    • one year ago
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    If you want the AREA of the BASE, that won't involve the height. The formula for area of a circle is A = pi*r^2 If your choices all include pi, then yes, the answer is 16 pi sq. units. If you post choices for a multiple choice question, it's important that you post exactly what the choices are. You can just type "pi" if you don't want to use the equation editor, but don't just ignore it.... :)

  9. anonymous
    • one year ago
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    I'm sorry! I'm new here lol So how would you find the lateral area for the same figure?

  10. DebbieG
    • one year ago
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    The volume of the cylinder would be V = h*pi*r^2 (area of the base x height). I don't think r*h*pi would be.... anything. :)

  11. anonymous
    • one year ago
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    lol sorry I'm not very good at math. Thanks. But can you help me with one more thing?

  12. DebbieG
    • one year ago
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    Lateral area would be the area of the outside of the cylinder, right? Without the bases. So you need to think of "unrolling" the cylinder. It would be a rectangle then, with height = h =6, and base = circumference = 2pi*r = 8pi.

  13. DebbieG
    • one year ago
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    No problem, that's what the site is for! :) If it's a new/different problem, you should really post it as a new question. :)

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