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anonymous
 one year ago
Let be a standard normal random variable. Use the calculator to determine the value of such that
P(c<=Z<=c)=.9265
anonymous
 one year ago
Let be a standard normal random variable. Use the calculator to determine the value of such that P(c<=Z<=c)=.9265

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DebbieG
 one year ago
Best ResponseYou've already chosen the best response.1Well, remember that the normal distribution is symmetric: dw:1434763714199:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0right so you divide it by 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now why did you add +.5?

DebbieG
 one year ago
Best ResponseYou've already chosen the best response.1The area between the mean (0) and c is .9265/2. And the area to the left of the mean is 0.5. So you need c such that the area to the left of c (the total area) is 0.96325

DebbieG
 one year ago
Best ResponseYou've already chosen the best response.1I think you use the inverse normal function in your calculator. I am not really familiar with doing them via calculator so I'd probably have to look up how to actually enter it... lol.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol we were actually taught on doing it on the calculator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think i would just do p(z<=.96325)

DebbieG
 one year ago
Best ResponseYou've already chosen the best response.1Yes, that should work. I used invNorm(0.96325,0,1) and got 1.7897

DebbieG
 one year ago
Best ResponseYou've already chosen the best response.1Can also use an online calculator like this one: http://stattrek.com/onlinecalculator/normal.aspx
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