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anonymous

  • one year ago

-7x^2=-448 taking the square root and completing the square please show steps

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  1. anonymous
    • one year ago
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    you do not have to complete the square for this one divide both sides by \(-7\) then take the square root of both sides don't forget the \(\pm\)

  2. max1409
    • one year ago
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    https://www.mathway.com

  3. pooja195
    • one year ago
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    \[\huge~\rm~-448\div-7=?\]

  4. anonymous
    • one year ago
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    64

  5. geerky42
    • one year ago
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    Yep, so now you have \(x^2 = 64\) Your next step is to take square root of both sides.

  6. pooja195
    • one year ago
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    \[\huge~\rm~\sqrt{x^2}=\sqrt{64}\]

  7. anonymous
    • one year ago
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    64 is 8

  8. pooja195
    • one year ago
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    good and the square root of X^2 ?

  9. anonymous
    • one year ago
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    x

  10. pooja195
    • one year ago
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    ok so whats the answer?

  11. anonymous
    • one year ago
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    8x

  12. anonymous
    • one year ago
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    so the equation for it would be like the steps

  13. pooja195
    • one year ago
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    Nope remeber the = sign it remains there! \[\huge~\rm~x=\pm8\]

  14. anonymous
    • one year ago
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    what would be the steps

  15. pooja195
    • one year ago
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    We just did it ... we need to divide both sides by -7 that way we can isolate the x \[\huge~\rm~\frac{ -7x^2=-448 }{ 7 } \] We were left with \[\huge~\rm~x^2=64\] we need to solve for x so we need to square root both of those \[\huge~\rm~\sqrt{x^2}=\sqrt{64}\]

  16. pooja195
    • one year ago
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    And when we did this we ended up with... \[\huge~\rm~x=\pm8\]

  17. pooja195
    • one year ago
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    understood ?

  18. anonymous
    • one year ago
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    yes i think so if i turned these steps it would be the correct formulas and stuff?

  19. pooja195
    • one year ago
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    Can you please rephrase that ?

  20. anonymous
    • one year ago
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    i'm suppose to show my work when i turn it in so if i turn these steps in would it be the correct formula?

  21. anonymous
    • one year ago
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    can you help me with one more?

  22. pooja195
    • one year ago
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    ._. this is correct but i expect u to be able to do the next one by yourself if it is like this...i can look over the work :)

  23. anonymous
    • one year ago
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    ok well the next one is a little different x^2-10x+22=-2

  24. anonymous
    • one year ago
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    do i do the same thing?

  25. pooja195
    • one year ago
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    We need to get it into standered for first \[\huge~\rm~ax^2+bx+c=0\]

  26. anonymous
    • one year ago
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    fill it in with the number from the equation?

  27. pooja195
    • one year ago
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    x^2-10x+22=-2 we add the -2 to the - \[\huge~\rm~22-2=?\]

  28. anonymous
    • one year ago
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    well -24

  29. pooja195
    • one year ago
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    my mistake sorry it would be just 24

  30. pooja195
    • one year ago
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    \[\huge~\rm~x^2-10x+24=0\]

  31. pooja195
    • one year ago
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    what numbers multiply to make 24 but adds to make -10

  32. anonymous
    • one year ago
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    4 an 6 im not sure

  33. pooja195
    • one year ago
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    good -4 and -6 then (x-6) (x-4) set up 2 diffrent equations x-6=0 <---solve for x x-4=0 <----solve for x

  34. anonymous
    • one year ago
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    x=6 and x=4

  35. anonymous
    • one year ago
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    @pooja195

  36. pooja195
    • one year ago
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    yep

  37. anonymous
    • one year ago
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    and then?

  38. pooja195
    • one year ago
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    thats it

  39. anonymous
    • one year ago
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    o so the steps are ?

  40. anonymous
    • one year ago
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    i got to go

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