anonymous
  • anonymous
-7x^2=-448 taking the square root and completing the square please show steps
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
you do not have to complete the square for this one divide both sides by \(-7\) then take the square root of both sides don't forget the \(\pm\)
max1409
  • max1409
https://www.mathway.com
pooja195
  • pooja195
\[\huge~\rm~-448\div-7=?\]

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More answers

anonymous
  • anonymous
64
geerky42
  • geerky42
Yep, so now you have \(x^2 = 64\) Your next step is to take square root of both sides.
pooja195
  • pooja195
\[\huge~\rm~\sqrt{x^2}=\sqrt{64}\]
anonymous
  • anonymous
64 is 8
pooja195
  • pooja195
good and the square root of X^2 ?
anonymous
  • anonymous
x
pooja195
  • pooja195
ok so whats the answer?
anonymous
  • anonymous
8x
anonymous
  • anonymous
so the equation for it would be like the steps
pooja195
  • pooja195
Nope remeber the = sign it remains there! \[\huge~\rm~x=\pm8\]
anonymous
  • anonymous
what would be the steps
pooja195
  • pooja195
We just did it ... we need to divide both sides by -7 that way we can isolate the x \[\huge~\rm~\frac{ -7x^2=-448 }{ 7 } \] We were left with \[\huge~\rm~x^2=64\] we need to solve for x so we need to square root both of those \[\huge~\rm~\sqrt{x^2}=\sqrt{64}\]
pooja195
  • pooja195
And when we did this we ended up with... \[\huge~\rm~x=\pm8\]
pooja195
  • pooja195
understood ?
anonymous
  • anonymous
yes i think so if i turned these steps it would be the correct formulas and stuff?
pooja195
  • pooja195
Can you please rephrase that ?
anonymous
  • anonymous
i'm suppose to show my work when i turn it in so if i turn these steps in would it be the correct formula?
anonymous
  • anonymous
can you help me with one more?
pooja195
  • pooja195
._. this is correct but i expect u to be able to do the next one by yourself if it is like this...i can look over the work :)
anonymous
  • anonymous
ok well the next one is a little different x^2-10x+22=-2
anonymous
  • anonymous
do i do the same thing?
pooja195
  • pooja195
We need to get it into standered for first \[\huge~\rm~ax^2+bx+c=0\]
anonymous
  • anonymous
fill it in with the number from the equation?
pooja195
  • pooja195
x^2-10x+22=-2 we add the -2 to the - \[\huge~\rm~22-2=?\]
anonymous
  • anonymous
well -24
pooja195
  • pooja195
my mistake sorry it would be just 24
pooja195
  • pooja195
\[\huge~\rm~x^2-10x+24=0\]
pooja195
  • pooja195
what numbers multiply to make 24 but adds to make -10
anonymous
  • anonymous
4 an 6 im not sure
pooja195
  • pooja195
good -4 and -6 then (x-6) (x-4) set up 2 diffrent equations x-6=0 <---solve for x x-4=0 <----solve for x
anonymous
  • anonymous
x=6 and x=4
anonymous
  • anonymous
@pooja195
pooja195
  • pooja195
yep
anonymous
  • anonymous
and then?
pooja195
  • pooja195
thats it
anonymous
  • anonymous
o so the steps are ?
anonymous
  • anonymous
i got to go

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