-7x^2=-448
taking the square root
and
completing the square
please show steps

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- anonymous

-7x^2=-448
taking the square root
and
completing the square
please show steps

- chestercat

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- anonymous

you do not have to complete the square for this one
divide both sides by \(-7\) then take the square root of both sides
don't forget the \(\pm\)

- max1409

https://www.mathway.com

- pooja195

\[\huge~\rm~-448\div-7=?\]

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## More answers

- anonymous

64

- geerky42

Yep, so now you have \(x^2 = 64\)
Your next step is to take square root of both sides.

- pooja195

\[\huge~\rm~\sqrt{x^2}=\sqrt{64}\]

- anonymous

64 is 8

- pooja195

good and the square root of X^2 ?

- anonymous

x

- pooja195

ok so whats the answer?

- anonymous

8x

- anonymous

so the equation for it would be like the steps

- pooja195

Nope remeber the = sign it remains there!
\[\huge~\rm~x=\pm8\]

- anonymous

what would be the steps

- pooja195

We just did it ...
we need to divide both sides by -7 that way we can isolate the x
\[\huge~\rm~\frac{ -7x^2=-448 }{ 7 } \]
We were left with
\[\huge~\rm~x^2=64\]
we need to solve for x so we need to square root both of those
\[\huge~\rm~\sqrt{x^2}=\sqrt{64}\]

- pooja195

And when we did this we ended up with...
\[\huge~\rm~x=\pm8\]

- pooja195

understood ?

- anonymous

yes i think so if i turned these steps it would be the correct formulas and stuff?

- pooja195

Can you please rephrase that ?

- anonymous

i'm suppose to show my work when i turn it in so if i turn these steps in would it be the correct formula?

- anonymous

can you help me with one more?

- pooja195

._. this is correct but i expect u to be able to do the next one by yourself if it is like this...i can look over the work :)

- anonymous

ok well the next one is a little different
x^2-10x+22=-2

- anonymous

do i do the same thing?

- pooja195

We need to get it into standered for first
\[\huge~\rm~ax^2+bx+c=0\]

- anonymous

fill it in with the number from the equation?

- pooja195

x^2-10x+22=-2
we add the -2 to the -
\[\huge~\rm~22-2=?\]

- anonymous

well -24

- pooja195

my mistake sorry it would be just 24

- pooja195

\[\huge~\rm~x^2-10x+24=0\]

- pooja195

what numbers multiply to make 24 but adds to make -10

- anonymous

4 an 6 im not sure

- pooja195

good -4 and -6 then
(x-6) (x-4)
set up 2 diffrent equations
x-6=0 <---solve for x
x-4=0 <----solve for x

- anonymous

x=6
and
x=4

- anonymous

- pooja195

yep

- anonymous

and then?

- pooja195

thats it

- anonymous

o so the steps are ?

- anonymous

i got to go

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