anonymous
  • anonymous
. .
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Someone in the mathematics chat room of openstudy is constantly spamming the chat. When he gets banned, he simply makes a new account and continues the spam. Could you possibly IP ban him?
anonymous
  • anonymous
Chethus this isn't a math question
anonymous
  • anonymous
whats the question ??

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anonymous
  • anonymous
I can't message Satellite so I tagged him in this
anonymous
  • anonymous
hmm....thats a good thought....useless idiot...
anonymous
  • anonymous
Who was that aimed towards?
anonymous
  • anonymous
he is probably like a cyber terrorist!!??LOL
anonymous
  • anonymous
Haha, maybe!
anonymous
  • anonymous
hmmm...whats ur age buddy?
anonymous
  • anonymous
15, but I am stupid :(
anonymous
  • anonymous
nothin like that...i am 17...
anonymous
  • anonymous
You should really help me with a question.
anonymous
  • anonymous
Well hey, your smarter then me so its all good
anonymous
  • anonymous
nobody is stupid...except attar!!
anonymous
  • anonymous
Linda is studying the sale of a particular brand of cereals from the year 1993 to 2004. She writes the following function to model the sale of the cereal S(t), in million dollars, after t years: S(t) = t2 + 5t + 52 Part A: What does the y-intercept of the graph of the function represent? (4 points) Part B: What is the reasonable domain of the graph of the function? (3 points) Part C: What is the average rate of change of the sale of the cereal from the first year to the fourth year? Show your work. (3 points) Can you help me with this? I asked this question in the chat but I couldn't read your and nincompoops replies because of the spam
anonymous
  • anonymous
yeah....did u understand the queastion bro?
anonymous
  • anonymous
Haha, nope. I am but a stupid teen
anonymous
  • anonymous
do u have the interest to learn?
anonymous
  • anonymous
I usually I would, but I've been stuck on this question since 9 :/
anonymous
  • anonymous
And since this is the second to last question on my test, I could care less if I know how to do this.
anonymous
  • anonymous
ok...see the first question...
anonymous
  • anonymous
i will tell u how to do this...
anonymous
  • anonymous
Alright, sounds good.
anonymous
  • anonymous
what do u mean by the y-intercept?
anonymous
  • anonymous
just concentrate buddy...
anonymous
  • anonymous
I don't understand what your trying to ask
anonymous
  • anonymous
Haha my brain is fried dude. I won't be able to think very well
anonymous
  • anonymous
Do you mean the whole y intercept represents the 0 on the x axis?
anonymous
  • anonymous
i am just trying to check wether u have visualized this question correctly...ok if u want some help...i shall attach a graph
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
Alright. Listen, I am very sorry to say this, and this is actually my first time ever saying this. But can you just give me the answers straight up? Like I said, I've been on this question for a long long time and I don't have the tolerance to learn how to do it anymore. This is the second to last question on my last assignment of the online class so learning this won't help me really that well at all. @chethus if you say you won't then I totally understand and will do it myself somehow.
anonymous
  • anonymous
ok....here is your answer....the y-intercept shows the sales for the year 1993
anonymous
  • anonymous
Alright, thank you. What about for part B?
anonymous
  • anonymous
yes...will tell u that
anonymous
  • anonymous
Alright, thanks. The ... is really making me feel bad you know
anonymous
  • anonymous
the reasonable domain to that function is the set of all positive values....because a measure of the number years cannot be negative
anonymous
  • anonymous
Alright, and part c?
anonymous
  • anonymous
yes...will tell u
anonymous
  • anonymous
the answer for the last one is 10...
anonymous
  • anonymous
hey ima, one more thing..the domain is actually t=0 to t=11
anonymous
  • anonymous
r u here buddy?
anonymous
  • anonymous
Yeah, I am. Sorry about that. Thank you so much for your time man
anonymous
  • anonymous
I also gave you a fan. Again, thank you
anonymous
  • anonymous
is there some option of inviting friends or something like that....or r u there on fb?
anonymous
  • anonymous
What do you mean?
anonymous
  • anonymous
The fan option?
anonymous
  • anonymous
like sending a friend request....or something like that..?
anonymous
  • anonymous
Oh, its a bit different on this site. If I fan you, you will be on this list of others that I fanned and I will get a notification when they get online. When you get fanned, you also get more smartscore.
anonymous
  • anonymous
So lets say you are offline right now, and decide to log on. I will get a notification saying "chethus is now online"
anonymous
  • anonymous
oh...i get it...i fanned u rite?i did it now...and r u there on fb?
anonymous
  • anonymous
Well I didn't get a notification saying you fanned me.
anonymous
  • anonymous
Do you see that icon on the top slightly to the left corner of the screen?
1 Attachment
anonymous
  • anonymous
It might not have the number 4 on it
anonymous
  • anonymous
yeah..it doesnt
anonymous
  • anonymous
how to fan people?
anonymous
  • anonymous
Just click on the username of the person you want to fan. A window showing the user's stats will appear. You should then see a button that says "Become a fan". Click on it. The image below shows you how
1 Attachment
anonymous
  • anonymous
yeah...did it...i can see you online

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