A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Does this have an absolute minimum?
f(x)=4(x^2−1)^3, [−1,2]
anonymous
 one year ago
Does this have an absolute minimum? f(x)=4(x^2−1)^3, [−1,2]

This Question is Closed

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Extreme value theorem http://mathworld.wolfram.com/ExtremeValueTheorem.html in that article, when they mention "minimum" they really mean "absolute minimum" a local min is possible, but it will always have a absolute min

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right, I was able to find the absolute max. at (2,108) but I couldn't find any abs min

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohh wait! I just found it! It's at (0,4)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yes (0,4) is the absolute min

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks so much!! Sorry, I just realized the answer!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.