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  1. anonymous
    • one year ago
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    If 5.40 kcal of heat is added to 1.00 kg of water at 100⁰C, how much steam at 100⁰C is produced? Show all calculations leading to an answer.

  2. Miracrown
    • one year ago
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    We need to know how much heat it takes to vaporize water into steam; its called the heat of vaporization. It takes 2260 joules to vaporize one gram of water. We want to know the grams we can vaporize, lets call that unknown "G". Then we can write G x 2260 = 5.40 x 1000 joules. We were give 5.4o kJ to use

  3. Miracrown
    • one year ago
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    \[(G) \space (2260) \space = 5.40 \times 1000 \space = 5400\] Solve that for G

  4. anonymous
    • one year ago
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    2.39g? @miracrown

  5. anonymous
    • one year ago
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    @Luigi0210 @Whitemonsterbunny17 @UsukiDoll @danish071996

  6. UsukiDoll
    • one year ago
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    oh wow! How did I end up in the science thread? I'm not even good at this.

  7. anonymous
    • one year ago
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    Makes two of us. Haha. @UsukiDoll

  8. UsukiDoll
    • one year ago
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    yeah :(

  9. UsukiDoll
    • one year ago
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    >_<.....I don't want to answer to science :( AHHHHHHHHHHHH!

  10. anonymous
    • one year ago
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    Sorry for long respond, I tried to understand it. I'm not good with chemistry too but from mira's explanation, we just have to evaluate the equation that she did and solve for the value of G, which is equal to.... 2.389380531 g we got the same :)

  11. Miracrown
    • one year ago
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    It is 2.40 g - you're right!

  12. anonymous
    • one year ago
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    How would you set it up if this was the formula for it? Q=m*Hv

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