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anonymous

  • one year ago

To solve the equation 3sin(2x) = 5cosx, you should rewrite it as____. A. 3sinx + 5cosx = 0 B. cosx(3sinx - 5) = 0 C. cosx(6sinx - 5) = 0

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  1. sdfgsdfgs
    • one year ago
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    hint: use eqn sin2A = 2sinAcosA

  2. anonymous
    • one year ago
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    I am want say A but I have a good feeling it is C

  3. sdfgsdfgs
    • one year ago
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    What happens to the 2x if A is the ans?

  4. anonymous
    • one year ago
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    Oh, now that I look at this way, I see that I don't see how 2x would go into A as the answer. Therefore taking that out of the equation right?

  5. anonymous
    • one year ago
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    *problem

  6. sdfgsdfgs
    • one year ago
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    correct :)

  7. anonymous
    • one year ago
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    Awesome! I don't think that B would be the answer because it would have to be '6sinx' instead of '3sinx' right?

  8. sdfgsdfgs
    • one year ago
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    also correct :)

  9. anonymous
    • one year ago
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    Cool! So that would make the answer C!

  10. anonymous
    • one year ago
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    Thank you for the time and help! I appreciate it!

  11. sdfgsdfgs
    • one year ago
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    welcome - u did most of the work urself! :)

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