## anonymous one year ago Let h = (v o^2 / 4.9) sin theta cos theta model the horizontal distance in meters traveled by a projectile. If the initial velocity is 52 meters/second, which equation would you use to find the angle needed to travel 200 meters? A. 551.84sin(2theta)=200 B. 275.92sin(2theta)=200 C. 10.61 sin(2theta)=100 D. 200 sin(2theta)=200

1. anonymous

I do not know where to go from this stage: $551.84\sin \Theta$

2. kropot72

You should use the double angle formula: $\large \sin 2\theta=2 \sin\theta \cos\theta$

3. anonymous

just tell me the proper equation

4. kropot72

Then we get $\large 200=\frac{52^{2}}{4.9}\times \frac{\sin 2\theta}{2}$

5. anonymous

Oh I understand! So that would get me the answer to be B right?

6. kropot72

Correct.

7. anonymous

Great! Thank you! It's always setting up the equation that gets me.

8. kropot72

np. You're welcome :)