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anonymous

  • one year ago

Let h = (v o^2 / 4.9) sin theta cos theta model the horizontal distance in meters traveled by a projectile. If the initial velocity is 52 meters/second, which equation would you use to find the angle needed to travel 200 meters? A. 551.84sin(2theta)=200 B. 275.92sin(2theta)=200 C. 10.61 sin(2theta)=100 D. 200 sin(2theta)=200

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  1. anonymous
    • one year ago
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    I do not know where to go from this stage: \[551.84\sin \Theta\]

  2. kropot72
    • one year ago
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    You should use the double angle formula: \[\large \sin 2\theta=2 \sin\theta \cos\theta\]

  3. anonymous
    • one year ago
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    just tell me the proper equation

  4. kropot72
    • one year ago
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    Then we get \[\large 200=\frac{52^{2}}{4.9}\times \frac{\sin 2\theta}{2}\]

  5. anonymous
    • one year ago
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    Oh I understand! So that would get me the answer to be B right?

  6. kropot72
    • one year ago
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    Correct.

  7. anonymous
    • one year ago
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    Great! Thank you! It's always setting up the equation that gets me.

  8. kropot72
    • one year ago
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    np. You're welcome :)

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