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anonymous

  • one year ago

A company that manufactures storage bins for grains made a drawing of a silo. The silo has a conical base, as shown below: Which of the following could be used to calculate the total volume of grains that can be stored in the silo? π(2ft)2(8ft) + one over threeπ(2ft)2(9.5ft − 8ft) π(8ft)2(2ft) + one over threeπ(2ft)2(9.5ft − 8ft) π(2ft)2(8ft) + one over threeπ(9.5ft − 8ft)2(2ft) <--- my answer π(8ft)2(2ft) + one over threeπ(9.5ft − 8ft)2(2ft)

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  1. anonymous
    • one year ago
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    @jim_thompson5910

  2. jim_thompson5910
    • one year ago
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    |dw:1434773162856:dw|

  3. jim_thompson5910
    • one year ago
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    |dw:1434773265813:dw|

  4. jim_thompson5910
    • one year ago
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    |dw:1434773328065:dw|

  5. anonymous
    • one year ago
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    1.5

  6. jim_thompson5910
    • one year ago
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    what is the volume of just the cylinder (ignore the cone)

  7. jim_thompson5910
    • one year ago
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    just provide the formula you don't have to calculate anything

  8. anonymous
    • one year ago
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    oh ok its 8 ft

  9. jim_thompson5910
    • one year ago
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    Volume of cylinder \[\Large V = \pi*r^2*h\]

  10. jim_thompson5910
    • one year ago
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    make the proper substitutions

  11. anonymous
    • one year ago
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    im having a little trouble but i know the height would be 18 but im confused on the others sorry

  12. anonymous
    • one year ago
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    im sorry i meant 8 not 18

  13. jim_thompson5910
    • one year ago
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    no the height isn't 18 the height of the cylinder is 8

  14. jim_thompson5910
    • one year ago
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    r = 2 h = 8 for the cylinder

  15. anonymous
    • one year ago
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    |dw:1434774102132:dw| is this right

  16. jim_thompson5910
    • one year ago
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    for the cone, r = 2 h = (9.5-8) volume of a cone formula \[\Large V = \frac{1}{3}\pi*r^2*h\]

  17. anonymous
    • one year ago
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    oh ok |dw:1434774377668:dw|

  18. jim_thompson5910
    • one year ago
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    Cylinder: \[\Large V_1 = \pi*r^2*h\] \[\Large V_1 = \pi*(2)^2*8\] Cone: \[\Large V_2 = \frac{1}{3}\pi*r^2*h\] \[\Large V_2 = \frac{1}{3}\pi*(2)^2*(9.5-8)\] Combine the two 3D figures \[\Large V_1 + V_2 = \pi*(2)^2*8+\frac{1}{3}\pi*(2)^2*(9.5-8)\]

  19. jim_thompson5910
    • one year ago
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    |dw:1434774521126:dw|

  20. anonymous
    • one year ago
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    @jim_thompson5910 would it be B ??

  21. jim_thompson5910
    • one year ago
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    look again at \[\Large \pi*(2)^2*8+\frac{1}{3}\pi*(2)^2*(9.5-8)\]

  22. jim_thompson5910
    • one year ago
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    and how I used the formulas to get that

  23. anonymous
    • one year ago
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    oh ok i see (:

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