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## anonymous one year ago A company that manufactures storage bins for grains made a drawing of a silo. The silo has a conical base, as shown below: Which of the following could be used to calculate the total volume of grains that can be stored in the silo? π(2ft)2(8ft) + one over threeπ(2ft)2(9.5ft − 8ft) π(8ft)2(2ft) + one over threeπ(2ft)2(9.5ft − 8ft) π(2ft)2(8ft) + one over threeπ(9.5ft − 8ft)2(2ft) <--- my answer π(8ft)2(2ft) + one over threeπ(9.5ft − 8ft)2(2ft)

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1. anonymous

@jim_thompson5910

2. jim_thompson5910

|dw:1434773162856:dw|

3. jim_thompson5910

|dw:1434773265813:dw|

4. jim_thompson5910

|dw:1434773328065:dw|

5. anonymous

1.5

6. jim_thompson5910

what is the volume of just the cylinder (ignore the cone)

7. jim_thompson5910

just provide the formula you don't have to calculate anything

8. anonymous

oh ok its 8 ft

9. jim_thompson5910

Volume of cylinder $\Large V = \pi*r^2*h$

10. jim_thompson5910

make the proper substitutions

11. anonymous

im having a little trouble but i know the height would be 18 but im confused on the others sorry

12. anonymous

im sorry i meant 8 not 18

13. jim_thompson5910

no the height isn't 18 the height of the cylinder is 8

14. jim_thompson5910

r = 2 h = 8 for the cylinder

15. anonymous

|dw:1434774102132:dw| is this right

16. jim_thompson5910

for the cone, r = 2 h = (9.5-8) volume of a cone formula $\Large V = \frac{1}{3}\pi*r^2*h$

17. anonymous

oh ok |dw:1434774377668:dw|

18. jim_thompson5910

Cylinder: $\Large V_1 = \pi*r^2*h$ $\Large V_1 = \pi*(2)^2*8$ Cone: $\Large V_2 = \frac{1}{3}\pi*r^2*h$ $\Large V_2 = \frac{1}{3}\pi*(2)^2*(9.5-8)$ Combine the two 3D figures $\Large V_1 + V_2 = \pi*(2)^2*8+\frac{1}{3}\pi*(2)^2*(9.5-8)$

19. jim_thompson5910

|dw:1434774521126:dw|

20. anonymous

@jim_thompson5910 would it be B ??

21. jim_thompson5910

look again at $\Large \pi*(2)^2*8+\frac{1}{3}\pi*(2)^2*(9.5-8)$

22. jim_thompson5910

and how I used the formulas to get that

23. anonymous

oh ok i see (:

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