TBNRfrags
  • TBNRfrags
Help pl0x http://prntscr.com/7j31oq
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
UsukiDoll
  • UsukiDoll
\[\frac{12x^4y^3z^2w}{2xy^2}\]
UsukiDoll
  • UsukiDoll
all we need to do is use division for the numbers only and use one of the exponent rules for the variables. \[\frac{x^a}{x^b} \rightarrow x^{a-b}\] where x = variable a and b = numbers so for the numbers only we have 12/2, so what's 12 divided by 2
TBNRfrags
  • TBNRfrags
6

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

UsukiDoll
  • UsukiDoll
yes.. so for the variables only we noticed that only x and y are present on the numerator and denominator, so we use the exponent law to figure this part out ... so if we let a = 4 and b = 1 from earlier \[\frac{x^4}{x^1} \rightarrow x^{4-1}\] we just have to subtract.. so what's 4-1 ?
TBNRfrags
  • TBNRfrags
3
UsukiDoll
  • UsukiDoll
alright so we have \[x^3\]
UsukiDoll
  • UsukiDoll
we do the same thing for the y variable because that exists on the numerator and denominator \[\frac{y^3}{y^2} \rightarrow y^{3-2}\] so all we need to do is subtract.. what is 3 -2 ?
TBNRfrags
  • TBNRfrags
1
UsukiDoll
  • UsukiDoll
yes so now we have just \[y^1 \] or you can write it as y only because it's to the first power... those 3 arithmetics we've just done are only necessary for this problem because z and w aren't present in the denominator, so we just leave them alone.
UsukiDoll
  • UsukiDoll
\[6x^3yz^2w\]
UsukiDoll
  • UsukiDoll
and that's our final answer.
TBNRfrags
  • TBNRfrags
tyvm<3

Looking for something else?

Not the answer you are looking for? Search for more explanations.