TBNRfrags one year ago Help pl0x http://prntscr.com/7j31oq

1. UsukiDoll

$\frac{12x^4y^3z^2w}{2xy^2}$

2. UsukiDoll

all we need to do is use division for the numbers only and use one of the exponent rules for the variables. $\frac{x^a}{x^b} \rightarrow x^{a-b}$ where x = variable a and b = numbers so for the numbers only we have 12/2, so what's 12 divided by 2

3. TBNRFrags

6

4. UsukiDoll

yes.. so for the variables only we noticed that only x and y are present on the numerator and denominator, so we use the exponent law to figure this part out ... so if we let a = 4 and b = 1 from earlier $\frac{x^4}{x^1} \rightarrow x^{4-1}$ we just have to subtract.. so what's 4-1 ?

5. TBNRFrags

3

6. UsukiDoll

alright so we have $x^3$

7. UsukiDoll

we do the same thing for the y variable because that exists on the numerator and denominator $\frac{y^3}{y^2} \rightarrow y^{3-2}$ so all we need to do is subtract.. what is 3 -2 ?

8. TBNRFrags

1

9. UsukiDoll

yes so now we have just $y^1$ or you can write it as y only because it's to the first power... those 3 arithmetics we've just done are only necessary for this problem because z and w aren't present in the denominator, so we just leave them alone.

10. UsukiDoll

$6x^3yz^2w$

11. UsukiDoll