briana.img
  • briana.img
Can someone walk me through this problem?
Mathematics
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briana.img
  • briana.img
Can someone walk me through this problem?
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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briana.img
  • briana.img
jim_thompson5910
  • jim_thompson5910
|dw:1434775004409:dw|
jim_thompson5910
  • jim_thompson5910
we are given arc EN = 54 degrees |dw:1434775166578:dw|

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jim_thompson5910
  • jim_thompson5910
so central angle NDE = 54 degrees |dw:1434775191543:dw|
jim_thompson5910
  • jim_thompson5910
then you'll use the inscribed angle theorem https://www.mathsisfun.com/geometry/circle-theorems.html to take half of the central angle (54) to get 54*(1/2) = 27 degrees |dw:1434775270730:dw|
briana.img
  • briana.img
@jim_thompson5910 oh kay i understand now so for this one it'd be 40?
jim_thompson5910
  • jim_thompson5910
yep
briana.img
  • briana.img
@jim_thompson5910 oh okay thank you so much!
jim_thompson5910
  • jim_thompson5910
you're welcome

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