At 2:00pm a car's speedometer reads 50mph, and at 2:10pm it reads 65mph. Use the Mean Value Theorem to find an acceleration the car must achieve.

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At 2:00pm a car's speedometer reads 50mph, and at 2:10pm it reads 65mph. Use the Mean Value Theorem to find an acceleration the car must achieve.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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ok, so do you understand the concept and how Mean Value Theorem works?
I know that the Mean Value Theorem states that \[\frac{ f(b) -f(a) }{ b-a }=f'(c)\]
yep all it means is that the average rate of change can be approximated to a constant so f(b) in this case is 65 mph f(a) is 50 b is 2:10 a is 2:00 f'(c) is the rate of change parallel to the curve, so in this case: the acceleration b-a = 10 mins = 0.166 hours f(b) - f(a) = 15 15/0.1666 =...?

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Ahhh the only thing I hadn't done when trying to solve it was converting the min to hours lol
Got it! Thanks so much!
coolski, props ;)

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