A large emerald with a mass of 982.7 grams was recently discovered in a mine. If the density of the emerald is 2.76grams over centimeters cubed, what is the volume? Round to the nearest hundredth when necessary and only enter numerical values, which can include a decimal point [Fill in the Blank]

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A large emerald with a mass of 982.7 grams was recently discovered in a mine. If the density of the emerald is 2.76grams over centimeters cubed, what is the volume? Round to the nearest hundredth when necessary and only enter numerical values, which can include a decimal point [Fill in the Blank]

Mathematics
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@Jack1 can u help me when ever u get the chance (:
sure mass = 982.7 grams Density = 2.76 g/cm^3 Volume = ? so Density = mass per unit of volume \(\Large D = \frac mV \) if m = 982.7 and D = 2.76 V = ??? \(\Large D = \frac mV \) \(\Large 2.76 = \frac {982.7}V \) Can you solve for V from here?
sorry i was from my computer again but would it be 276.92??

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no i got a different answer, how did u calculate that?
sorry i think i calculated it wrong
s'ok \(\Large 2.76 = \frac {982.7}V\) multiply both sides by V \(\Large 2.76 \times V = \frac {982.7}V \times V\) V's now cancel out on the Right Hand Side, so you left with \(\Large 2.76 \times V = 982.7\) now divide both sides by 2.76 \(\Large \frac {2.76 \times V}{2.76} = \frac {982.7}{2.76}\) 2.76 over 2.76 on Left Hand Side = 1 \(\Large V = \frac {982.7}{2.76}\) so answer = ?
i divided and got 356.05 was i suppose to divided ??
356.05 = perfect answer, nicely done
Giid job Moo Moo
Good
Thank you ^w^ and really geek lol
hurry up amanda
nice spelling there geek ;P
hey jack would it be ok if u could help me with 4 more questions :D
Ty Goku Jack
lol ;)
ill help too
yo, sure, close this one off tho, it's all LaTex'd up again
I hate the latex subject
oh ok ^w^ thank you

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